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forsale [732]
3 years ago
9

Tan9 - tan27 - tan63 + tan 81 = ?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0
Tan9−tan27−tan63−tan81
tan9+tan81−tan27−tan63
sin9/cos9+sin81/cos81−sin27/cos27−sin63/cos63
sin90/cos81cos9−sin90/cos63cos27
1/sin9cos9−1/sin27cos27
2/sin18−2/sin54
(2)sin54−sin18/sin18sin54
4cos36sin18/sin18cos36=4
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***<br> -6<br> Simplify 21v6 ÷ (-7v-6)<br> O 0<br> -3y¹2<br> -3<br> 12<br> 0 -3<br> DONE<br> 0 0
-Dominant- [34]

Answer:

-3

Step-by-step explanation:

\frac{  21y {}^{ - 6} }{ - 7y {}^{ - 6} }  \\  - 3y {}^{ - 6 - ( - 6)}  \\  - 3y {}^{ - 6 + 6}  \\  - 3y {}^{0}  \\  - 3(1) \\  - 3

3 0
2 years ago
A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nea
Viktor [21]

Answer: 0.476

Step-by-step explanation:

Let A = Event of choosing an even number ball.

B = Event of choosing an 8 .

Given, A lottery game has balls numbered 1 through 21.

Sample space: S= {1,2,3,4,5,6,7,8,...., 21}

n(S) = 21

Then, A= {2,4,6,8, 10,...(20)}

i.e. n(A)= 10

B= {8}

n(B) = 1

A∪B = {2,4,6,8, 10,...(20)} = A

n(A∪B)=10

Now, the probability of selecting an even numbered ball or an 8 is

P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}

=\dfrac{10}{21}\approx0.476

Hence, the required probability =0.476

7 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
Solving quadratic equations using the quadratic formula.
mixer [17]

Answer:

what is there supposed to be a picture

8 0
3 years ago
An element with mass 590 grams decays by 19. 5% per minute. How much of the element is remaining after 15 minutes, to the neares
solmaris [256]

Answer:

Step 1

Formulate a recursive sequence modeling the number of grams after n  minutes.

we have that

100%-17.1%-------------- > 82.9%------------> 0.829

a(n) = 780*[0.829^n]

for n=19 minutes

a(19)=780*[0.829^(19)]=22.1121 g---------------> 22.1 g

the answer is 22.1 g

Step-by-step explanation:

5 0
3 years ago
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