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Ksivusya [100]
3 years ago
8

Solve for t. -2(t + 1) = -6

Mathematics
1 answer:
padilas [110]3 years ago
7 0
The correct answer is t will equal 2
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Let X be a continuous random variable with density functionf(x)={1−|x|0 for −1
BlackZzzverrR [31]

Answer:

f_Y (y) =\frac{d}{dy} = 2 \frac{1}{2 |\sqrt{y}|} -1 = \frac{1}{|\sqrt{y}|} -1,0 \leq Y\leq 1

Step-by-step explanation:

For this case we want to find the density function for Y=X^2

And we have the following density function for the random variable X:

f(X) = 1- |X|,-1 \leq X \leq 1

So we can do this replacing Y=X^2

F_Y (Y \leq y) = P(X^2 \leq y)

If we apply square root on both sides we got:

P(-\sqrt{y} \leq X \leq \sqrt{y}) = \int_{-\sqrt{y}}^0 1+t dt +\int_{0}^{\sqrt{y}} 1-t dt

And if we integrate we got this:

F_Y (y) = [t+ \frac{t^2}{2}] \Big|_{-\sqrt{y}}^0+ [t -\frac{t^2}{2}] \Big|_{0}^{\sqrt{y}}

And replacing we got:

F_Y (y) = [0 -(-\sqrt{y} +\frac{y}{2})] + [\sqrt{y} -\frac{y}{2}]

F_Y (y) = 2 |\sqrt{y}| -y

And if we want to find the density function we just need to derivate the pdf like this:

f_Y (y) =\frac{d}{dy} = 2 \frac{1}{2 |\sqrt{y}|} -1 = \frac{1}{|\sqrt{y}|} -1,0 \leq Y\leq 1

3 0
4 years ago
Which binomial is a factor of 12x^2 - x - 20
stellarik [79]

Answer:

12x² - x - 20 = (4x+5)(3x−4)

3 0
3 years ago
A ladder 7 m long stands on level ground and makes a 73° angle with the ground as it rests against a wall. How far from the wall
Sati [7]

Answer:

2 ft from the wall

Step-by-step explanation:

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3 years ago
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What is y=8/3x-68/3 in standard form?
lawyer [7]

Answer:

The standard form of this equation is -8x + 3y = -68

Step-by-step explanation:

In order to find this, first solve for the constant.

y = 8/3x - 68/3

-8/3x + y = -68/3

Now we multiply by 3 to get them all equal to integers.

-8x + 3y = -68

8 0
3 years ago
Consider the sequence of steps to solve the equation: 3(x - 4) + 5x 9x - 36
Zielflug [23.3K]

Answer:

Distributive Property

Step-by-step explanation:

You are distributing 3 to x and -4

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