Question

Forty-seven percent of fish in a river are catfish. Imagine scooping out a simple random sample of 25 fish from the river and observing the sample proportion of catfish. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 catfish in the river.
The standard deviation is 0.0998. The 10% condition is not met because there are less than 250 catfish in the river.
The standard deviation is 0.9002. The 10% condition is met because it is very likely there are more than 250 catfish in the river.
The standard deviation is 0.9002. The 10% condition is not met because there are less than 250 catfish in the river.
We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 250 catfish in the river.

Answer 1

Answer:

Therefore the correct option is a.) The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 catfish in the river.

Step-by-step explanation:

i) Let p = 0.47

ii) therefore q = 1 - 0.47 = 0.53

iii) sample size, n =25

iii) standard deviation = $\sqrt{\frac{p \times q}{n} } = \sqrt{\frac{0.47 \times 0.53}{25} } = 0.0998$

Therefore the correct option is

a.) The standard deviation is 0.0998. The 10% condition is met because it

    is very likely there are more than 250 catfish in the river.