Question

How many zero pairs must be added to the function

Answer 1

Answer:

Option 4 - 25

Step-by-step explanation:

Given : Function $f(x)=x^2-10x-4$

To find : How many zero pairs must be added to the function  in order to begin writing the function in  vertex form?

Solution :

The vertex form is $y=(x-h)^2+k$

Let function $y=x^2-10x-4$

Applying completing the square,

Add and subtract square of half of the coefficient of x,

i.e. $(\frac{-10}{2})^2=(5)^2$

$y=x^2-10x-4+(5)^2-(5)^2$

$y=x^2-2\times 5\times x+(5)^2-4-25$

$y=(x-5)^2-29$

Therefore, the zero pairs must be added to the function  in order to begin writing the function in  vertex form is 25.

So, Option 4 is correct.