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ratelena [41]
3 years ago
14

find the area under the standard normal curve that lies outside the interval between z=-2.73and z=-1.39

SAT
1 answer:
Natasha_Volkova [10]3 years ago
4 0

Answer:

0.9209

Explanation:

For a  normally distributed random variable,  the only way to find areas is using the z score. The z score is given by the equation:

z=\frac{x-\mu}{\sigma}

Where μ is the mean, σ is the standard deviation and x is the raw score to be measured.

The area under the standard normal curve that lies between the interval z=-2.73 and z=-1.39

From the z table, Area between -2.73 and -1.39 = P(z < -1.39) - P(z < -2.73) = 0.0823 - 0.0032 = 0.0791

Since the Area between -2.73 and -1.39 is 0.0791, the are outside the interval = 1 - 0.0791 = 0.9209

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