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Vesnalui [34]
3 years ago
8

Please show work

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0

(1)

since both equations express y in terms of x, equate the right sides

- 2x = - 4x + 10 ( subtract 4x from both sides )

2x = 10 ( divide both sides by 2 )

x = 5

substitute x = 5 into y = - 2x → y = - 10

solution is : (x, y ) → (5, - 10 )

(2)

equate the right sides of both equations

3x = 2x - 7 ( subtract 2x from both sides )

x = - 7

substitute x = - 7 into y = 3x → y = - 21

solution is : (x, y) → (- 7, - 21)

(3)

substitute y = - 8 into the other equation

- 8 = 6x + 22 ( subtract 22 from both sides )

- 30 = 6x ( divide both sides by 6 )

x = - 5

solution is : (x, y ) → (- 5, - 8 )



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3 times

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She would have to weigh the fake coins and another bag of real coins to spot a difference, and then she would need to check another bag to see which was correct. Maybe thats right.

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Need help plz?????????!!!!!!
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Answer:

93°

Step-by-step explanation:

By exterior angle theorem:

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(4x + 9)° = (2x + 3x - 12)°

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Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).
inna [77]

Answer:

\huge{ \fbox{ \sf{ \: ( \: 3 \: ,  \:  - 1 \: )}}}

Step-by-step explanation:

\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}

\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and  \: B(-2,-8) \: be \: (x2 \:, y2)}}

\underline{ \sf{Finding \: the \: midpoint}}

\boxed{ \rm{Midpoint \:  =  \: ( \frac{x1 + x2}{2}  \: ,  \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{8 + ( - 2)}{2}  \: ,  \:  \frac{6 + ( - 8)}{2} )}}

\mapsto { \sf{Midpoint = ( \frac{8 - 2}{2}  \: ,  \:  \frac{6 - 8}{2} }})

\mapsto{ \sf{Midpoint = ( \frac{6}{2}  \: ,  \:  \frac{ - 2}{2}) }}

\mapsto{ \sf{Midpoint = (3 \: \:  ,   - 1)}}

Hope I helped!

Best wishes!! :D

~\sf{TheAnimeGirl}

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The answer may be C hope helped
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