Answer:
v = 27
Step-by-step explanation:
20 = v + 9 - 16
20 = v + (9 - 16)
20 = v - 7
v = 27
Answer:
I had this question, photomath works.
Step-by-step explanation:
Answer:
cot(∅) = 
Step-by-step explanation:
tan ∅ and cot ∅ are inverse functions
therefore the inverse of
tan ∅ = √15 / 10
is equal to
cot ∅ = 10 / √15
Rationalizing the denominator
* 
cot ∅ =
Answer:
Step-by-step explanation:
27^x = 9÷(3^x)
So (3^3)^x = (3^2)÷(3^x)
So 3^3x = 3^(2-x)
Comparing powers on both sides,
3x = 2 - x
So, 4x = 2
So, x = 1/2
Given ( 27 ) ^ x = 9 / 3 ^x
⇒ ( 3 × 3 × 3 )^x = ( 3 × 3 ) / 3^x
⇒ ( 3 ³ )^x = 3² / 3^x
⇒ 3 ^ 3x × 3^x = 3² [ since ( a ^m)^n = a ^mn ]
⇒ 3^ (3x +x) = 3² [ since a^m × a^n = a ^m+n ]
⇒ 3^4x = 3²
⇒4x = 2 [ since If a ^m = a ^n then m = n ]
⇒ x = 2 / 4
∴ x = 1 / 2
I hope this helps you.
Answer:
There are an infinite number of values satisfying the requirements; every couple of numbers satisfying the following conditions are valid:
base = 60-w meters
width = w meters
0 < w <= 22
Step-by-step explanation:
Since the playground has a rectangular shape, let us us call b the base of the rectangle and w its width. In order for the rectangle to satisfy the condition of P = 120, we need for the following equation to satisfy:
2b + 2w = 120
Solving for b, we get that b = (120 - 2w)/2 = 60 - w .
Given a particular value (w) for the width, the base has to be: (60-w).
Therefore, the possible lengths of the playground are (60-w, w), where 60-w corresponds to the base of the rectangle and w to its width. And w can take any real value from 0 to 22.
