Given :
Michaela runs to the end of her street and back in 90 s.
Her brother, Jacob, walks to the end of the street and back in 3 min.
They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob.
To Find :
How many times did each person go to the end of the street and back.
Solution :
Let, they both walk for T seconds.
Number of rounds Michaela walk is, n₁ = T/90 .
Number of rounds Jacob walk is, n₂ =T/180 .
It is given that :
n₁ = n₂ + 5
T/90 + T/180 = 5
( T/90 + T/180 ) × 180 = 5×180
2T + T = 900
3T = 900
T = 300 s
So, n₁ = 300/90 = 3
n₂ = 1
Hence, this is the required solution.
Answer: Both the metal casing and tip of the bulb are connected to the circuit, forming a closed circuit. Thus, electricity is able to flow through the wires in the circuit to the filament, allowing the bulb to light up.
Answer choice B is wrong because y-y^1 not y-x^1 which also means that answer choice D is wrong because you cannot do a number minus a negative.
Answer choice A is wrong because y-y^1=m(x-x^1) remember, you cannot subtract a negative so it becomes posotive which means that answer choice C is your best bet
Have a nice day!
Answer:
0, -10
Step-by-step explanation:
150,165,180,198,204,216,230,255
Quartile 1: (165+180)÷2
=345÷2
=172.5
Quartile 3: (216+230)÷2
=446÷2
=223
Quartile range:223-172.5=50.5 or D. Hope it help!