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Gekata [30.6K]
2 years ago
11

The swimming pool at Spring Valley High School is a rectangle with a width of 75 meters and a length of 35 meters. Around the pe

rimeter of the pool is a tiled floor that extends w meters from the pool on all sides. Find an expression for the area of the tiled floor.
Mathematics
1 answer:
stealth61 [152]2 years ago
4 0
Same as before

total=(2w+75)(2w+35)=4w²+220w+2625

pool=75 times 35=2625

minus pool from total
4w²+220w+2625-2625=4w²+220w
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Listed below are prices in dollars for one night at different hotels in a certain region. Find the​ range, variance, and standar
Vanyuwa [196]

Answer:

Range = $115

Variance = $1915.2857

Standard deviation = $43.764

Step-by-step explanation:

Given the data:

234 160 119 131 218 207 146 141

Arranging in ascending order :

119, 131, 141, 146, 160, 207, 218, 234

The range = maximum - minimum

The range = 234 - 119 = 115

The variance :

Σ(x - mean)²/n-1

The mean = Σx / n

The mean = 1356 / 8 = 169.5

Variance :

Σ(x - mean)² = (119-169.5)² + (131-169.5)² + (141-169.5)² + (146-169.5)² + (160-169.5)² + (207-169.5)² + (218-169.5)² + (234-169.5)² = 13407

n - 1 = 8 - 1 = 7

Variance = 13407 / 7 = 1915.2857

Standard deviation = √variance

Standard deviation = √1915.2857

Standard deviation = $43.764

8 0
2 years ago
a fishing tackle box is 13 inches long 6 inches wide and 2 1/2 inches high. what is the volume of the tackle box
grandymaker [24]

Answer:

195 cubic inches

Step-by-step explanation:

A fishing tackle box is 13 inches long, 6 inches wide, and inches high. What is the volume of the tackle box? SOLUTION: The volume of the tackle box is 195 cubic inches.

7 0
2 years ago
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

4 0
3 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
Can anyone help with math models?? Please…?
Solnce55 [7]

Answer:

12*1/4= 3

30 is C

16*3/4 = 12

31 is B

8 0
2 years ago
Read 2 more answers
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