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TEA [102]
3 years ago
15

Please answer all please​

Mathematics
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

Step-by-step explanation:

The first parabola has vertex (-1, 0) and y-intercept (0, 1).

We plug these values into the given vertex form equation of a parabola:

y - k = a(x - h)^2 becomes

y - 0 = a(x + 1)^2

Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:

1 = a(0 + 1)^2, and from this we know that a = 1.  Thus, the equation of the first parabola is

y = (x + 1)^2

Second parabola:  We follow essentially the same approach.  Identify the vertex and the two horizontal intercepts.  They are:

vertex:  (1, 4)

x-intercepts:  (-1, 0) and (3, 0)

Subbing these values into y - k = a(x - h)^2, we obtain:

                                            0 - 4 = a(3 - 1)^2, or

                                                -4 = a(2)².  This yields a = -1.

Then the desired equation of the parabola is

y - 4 = -(x - 1)^2

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<u><em>Note:</em></u>

<em>Your question is a little unclear. But, from my understanding, I assume you may be asking the evaluation of the expression 36x - y when x = 3 and y = -6.</em>

<em>so I will solve based on my assumption which anyways would clear your concept.</em>

Answer:

The value of 36x - y when x = 3 and y = -6 will be: 114

Step-by-step explanation:

Given

Assuming the expression

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To Determine

Evaluate 36x - y when x = 3 and y = -6

Given the expression

36x - y

substitute x = 3 and y = -6 to evaluate the expression

36x-y= 36(3) - (-6)

            = 108+6

            = 114

Therefore, the value of 36x - y when x = 3 and y = -6 will be: 114

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