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Yuliya22 [10]
3 years ago
13

What does square mile mean

Mathematics
2 answers:
cestrela7 [59]3 years ago
6 0
<span>The square mile (abbreviated as sq mi and sometimes as mi2) is an imperial and US unit of measure for an area equal to the area of a squareof one statute mile. It should not be confused with miles square, which refers to the number of miles on each side squared.</span>
klasskru [66]3 years ago
6 0
A square mile is a mile side to side and a mile up and down
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Kai is conducting a study about the percentage of students with jobs. His school has 2500 students. He asks everyone in his dram
Evgesh-ka [11]

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3 years ago
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83. 6 in a complex number
grin007 [14]

Answer:

83.6 is a real number

Step-by-step explanation:

Since 83.6 83.6 is a real number, it is the real part (a) of the complex number a+bi a + b i . A real number does not contain any imaginary parts, so the value of b b is 0 0 . The answer is 83.6+0i 83.6 + 0 i

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4 years ago
Phil is riding his bike. He rides 46 miles in 4 hours, 57.5 miles in 5 hours, and 69 miles in 6 hours. Find the constant of prop
FromTheMoon [43]

Answer:

The constant of proportionality k = 11.5.

The equation will be: \mathbf{y=11.5(x)}

Step-by-step explanation:

If x represents number of hours than y represents miles

We are given:

x        y

4         46

5         57.5

6         69

The constant of proportionality can be found using formula: k=\frac{y}{x}

Putting values and finding k

x        y               k (k=\frac{y}{x})

4         46            11.5

5         57.5         11.5

6         69            11.5

So, the constant of proportionality k = 11.5

Now, The equation will be:

k=\frac{y}{x}\\or \\y=kx\\Put \ k=11.5\\y=11.5(x)

So, the equation will be: \mathbf{y=11.5(x)}

4 0
3 years ago
What is the derivative of f(x)= 3cos^2 (x)
Igoryamba
\large\begin{array}{l} \textsf{Finding the derivative of}\\\\ \mathsf{f(x)=3\,cos^2\,x} \end{array}

\large\begin{array}{l} \textsf{You can differentiate it using the chain rule}\\\\ \mathsf{f'(x)=(3\,cos^2\,x)'}\\\\ \mathsf{f'(x)=3\,(cos^2\,x)'}\\\\ \mathsf{f'(x)=3\cdot 2\,(cos\,x)^{2-1}\cdot (cos\,x)'}\\\\ \mathsf{f'(x)=6\,(cos\,x)^1\cdot (-sin\,x)}\\\\ \boxed{\begin{array}{c}\mathsf{f'(x)=-6\,cos\,x\,sin\,x} \end{array}}\qquad\checkmark \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2141400</span>


\large\textsf{I hope it helps.}


Tags: <em>derivative trig function cosine cos power chain rule differential calculus</em>

3 0
3 years ago
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Answer this one correctly !!!
kakasveta [241]
D is the correct answer


v = y



good luck
4 0
3 years ago
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