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3 years ago

What is the least common denominator (LCD) of 7/10 and 12/5

Mathematics

1 answer:

ioda3 years ago

5 0

The LCD of 7 and 10 is 70 and the LCD of 12 and 5 is 60

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What is the absolute value of:<br><br> -3|2y-3|+2=-20

Sladkaya [172]

Answer:

Exact Form:

y = 31/6, −13/6

Decimal Form:

y = 5.16,−2.16

Mixed Number Form:

y = 5 1/6,−2 1/6

7 0

1 year ago

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²

AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}$

Where ,

d₁ and d₂ are the Diagonals.

We have,

Diagonals as AC and BD,

Using Distance Formula we get

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting coordinates A and C we get

$l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit$

Similarly for BD we have,

$l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit$

Now Substituting AC and BD in Formula we get

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD$

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}$

Therefore the Area of Rhombus ABCD is 36 unit².

6 0

3 years ago

Judy wants to buy juice boxes at the lowest unit rate. Which is the best

Fudgin [204]

C would be the lowest cost at 91 cents per juice box

5 0

3 years ago

Read 2 more answers

Y = 4x - 7 <br> What is the y-intercept?

RideAnS [48]

Answer:

(0,-7)

Step-by-step explanation:

6 0

3 years ago

PLEASSSE HELP ASAP PRETTY PLEASEEEEEEE

IRISSAK [1]

I think the answer is C

7 0

3 years ago