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Agata [3.3K]
3 years ago
15

Recycling Center A processes aluminum at a rate of 100 pounds per hour, while Recycling Center B processes aluminum at a rate of

2 tons per week. Assuming that both centers operate all day every day, which center processes aluminum faster, and why?
Mathematics
2 answers:
ira [324]3 years ago
7 0
I think it's A aswell.
maria [59]3 years ago
6 0
I believe it is Recycling center A
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Simplify the given expression below:
ira [324]
The answer is A. -2+5i.

First you set up the problem like this: (6+2i)-(8-3i)
Then you distribute the (-) into the second parenthesis. After doing that you should have something that looks like this: 6+2i-8+3i
Then you add like terms.
6 0
2 years ago
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A package of twelve cans of the black beans cost $6.84. What is the cost of three cans of black beans?
valkas [14]

Answer:

$1.66

Step-by-step explanation:

First you need to divide $6.74 by 12 then you will get $0.55. Next you need to multiply $0.55 by 3 cans of black beans and you should get $1.66.

6 0
2 years ago
The sum of three integers is 228. The second integer is 1 more than the first, and the third integer is 2 more than the first. W
MaRussiya [10]
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7 0
3 years ago
Bob has 7 oranges, 10 plums and 4 pears in a bowl. He can choose: an orange and a plum or a plum and a pear or an orange, a plum
atroni [7]
In statistics the word "and" symbolized for multiplaction operation and the word "or" symbolized addition operation. so the number of ways can bob choose a fruit from the bowl is :

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7 0
3 years ago
What is √-11 in the form a+bi?
Mice21 [21]

Given:

The number is \sqrt{-11}.

To find:

The a+bi form of given number.

Solution:

We have,

\sqrt{-11}

It can be written as

\sqrt{-11}=\sqrt{-1\times 11}

\sqrt{-11}=\sqrt{-1}\times \sqrt{11}      [\because \sqrt{ab}=\sqrt{a}\sqrt{b}]

\sqrt{-11}=i\times \sqrt{11}      [\because \sqrt{-1}=i]

\sqrt{-11}=\sqrt{11}i

Here, real part is missing. So, it can be taken as 0.

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So, a = 0 and b=\sqrt{11}.

Therefore, the a+bi form of given number is 0+\sqrt{11}i.

5 0
2 years ago
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