Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is




Slope of lines NY is




Product of slopes of two perpendicular lines is -1. So,


The perpendicular bisector of NY passes through (-4,1) with slope
. So, the equation of perpendicular bisector of NY is




Add 1 on both sides.

Therefore, the equation of perpendicular bisector of NY is
.
I think the Answer is 44 copies per minute
143/3.25 = 44
C and D bc +-0.7 is the answer
but because there no answer which contains both i think u should mark E