Answer:
100
Step-by-step explanation:
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
Answer:
Step-by-step explanation:
Given the function :
y=x³ - 3x² - 9x + 2. The largest and smallest values of the function at interval [-2, 4]
We substitute x values in the interval (-2 to 4) into the equation and solve for y
At x = - 2
y = (-2)³ - 3(-2)² - 9(-2) + 2 = 0
At x = - 1
y = (-1)³ - 3(-1)² - 9(-1) + 2 = 7
At x = 0
y = (-0)³ - 3(-0)² - 9(-0) + 2 = 2
At x = 1
y = (1)³ - 3(1)² - 9(1) + 2 = - 9
At x = 2
y = (2)³ - 3(2)² - 9(2) + 2 = - 20
At x = 3
y = (3)³ - 3(3)² - 9(3) + 2 = - 25
At x = 4
y = (4)³ - 3(4)² - 9(4) + 2 = - 18
Function is greatest at
C is the answer I got it right
180=11+2x
-11 -11
169/2=2x\2
x=84.5
