D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, in ascending order
Q2 (median) = d5 = 2 //value in the middle
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 is middle value of d1,d2,d3,d4, but there is no middle element among four elements, that is why arithmetic mean is taken)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquantlie range = IQR = Q3 - Q1 = 5 -1 = 4
answer: 4
Answer:
The possible number of goats is 6 and the possible number of chicken is 24
Step-by-step explanation:
Let
chicken=c
Goat=g
the number of chickens could be four times the number of goats
c=4g
Total number of animals=30
c+g=30
Recall, c=4g
So,
c+g=30
4g+g=30
5g=30
Divide both sides by 5
5g/5=30/5
g=6
Recall,
c+g=30
c+6=30
c=30-6
=24
c=24
The possible number of goats is 6 and the possible number of chicken is 24 making a total of 30 animals
Answer:
See below ~
Step-by-step explanation:
<u>Given</u>
- Maitri and Aabhas do a work in 12 hours
- Aabhas and Kavya do the work in 15 hours
- Kavya and Maitri do the work in 20 hours
<u>Solving</u>
- Take Maitri, Aabhas, and Kavya to be x, y, z respectively
- <u>x + y = 12</u> (1)
- <u>y + z = 15</u> (2)
- <u>x + z = 20</u> (3)
<u>Take Equation 1 and rewrite it so that it is equal to x.</u>
<u>Take Equation 2 and rewrite it so that it is equal to z.</u>
<u>Now, substitute these values in Equation 3.</u>
- x + z = 20
- 12 - y + 15 - y = 20
- -2y + 27 = 20
- 2y = 7
- y = 7/2 = <u>3.5 hours [Aabhas]</u>
<u></u>
<u>Substitute the value of y in Equation 1.</u>
- x + 3.5 = 12
- x = <u>8.5 hours [Maitri]</u>
<u>Substitute the value of y in Equation 2.</u>
- 3.5 + z = 15
- z = <u>11.5 hours [Kavya]</u>
<u></u>
<u>Add the values of x, y, and z together.</u>
- x + y + z
- 8.5 + 3.5 + 11.5
- 12 + 11.5
- <u>23.5 hours [together]</u>
Answer:
real numbers
Step-by-step explanation:
