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Naily [24]
3 years ago
10

Which situation would be represented by zero? An altitude of 37 feet. An altitude of 7 meters below sea level. An altitude of 8

meters above sea level. An altitude at sea level.
Mathematics
2 answers:
kirza4 [7]3 years ago
7 0

Answer: an altitude at sea level

Korvikt [17]3 years ago
4 0

Answer:

an altitude at sea level

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Sean makes 2 pizzas he gives 8 people an equal share
Nataly [62]
2/8 = 1/4.
Each person gets 1/4 of a pizza.
7 0
3 years ago
Annie walks 15 feet away from her house and places a mirror on the ground. She backs 4 feet away from the mirror so that she can
Firdavs [7]

Answer:

18.75 ft

Step-by-step explanation:

The given scenario can be drawn as shown in the following attachment.

Given that,

m\angle DCE=\angle ACB and m\angle DEC=\angle ABC=90^{\circ}

Therefore, \Delta ABC\sim \Delta DEC

\Rightarrow \dfrac{AB}{DE}=\dfrac{BC}{EC}

\Rightarrow \dfrac{AB}{5}=\dfrac{15}{4}

\Rightarrow AB=\dfrac{15\times 5}{4}=18.75 ft

AB is the height of the house.

7 0
3 years ago
Read 2 more answers
a bowl contains 4 peaches and 4 apricots. Maine randomly selects one, puts it back, and randomly selects another. what is the pr
almond37 [142]
1/4 or 25% because...

The probability that Maine picks an apricot is 4/8

The probability that Maine picks an apricot after putting the first apricot back is still 4/8

4/8 x 4/8 = 16/64 = 1/4
4 0
2 years ago
A Cell Phone company sells cellular phones and airtime in a State. At a recent meeting, the marketing manager states that the av
GarryVolchara [31]

Answer:

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

The sample does not support the manager claim (the average age seems to differ from 40 years).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The manager claims that the average age of customers is 40 years. As this is an equality, we will test if the average age differs from 40. If the null hypothesis failed to be rejected, the claim of the manager is right.

Then, the claim is that the average age of the customers differs from 40 years.

Then, the null and alternative hypothesis are:

H_0: \mu=40\\\\H_a:\mu\neq 40

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=38.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7}{\sqrt{50}}=0.99

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{38-40}{0.99}=\dfrac{-2}{0.99}=-2.02

The degrees of freedom for this sample size are:

df=n-1=50-1=49

This test is a two-tailed test, with 49 degrees of freedom and t=-2.02, so the P-value for this test is calculated as (using a t-table):

P-value=2\cdot P(t

As the P-value (0.049) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

3 0
3 years ago
Need help with this math
olganol [36]

Hi,

Here is the solution.

3 years = 36 months

Leased amount for 3 years = $3000 + 36*350

= $3000 + $12600

Leased amount for 3 years = $15600

Residual value = $12000

Assume you didn't buy the car, you took it for lease, so your expense = $15600.

Now Assume you bought the car for $21,000.

After using 3 years, you can sell it for $12000.

Your expense = $21,000 - $12,000 = $9000.

Conclusion:

It is less expensive to buy the car.

The cost for buying the car and selling it after 3 years = $9000.

Hope you will understand the steps. Thank you :)

3 0
2 years ago
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