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Likurg_2 [28]
4 years ago
8

Using the phase plane program described in the introduction, plot the phase plane for the Lotka-Volterra model Here represents t

he population of a prey species, say mice, and is the population of a predator species, for example owls. If there are no owls, then the population of of mice grows exponentially, and if there are no mice, then the owls die off. However if the initial populations are both positive, then interesting stuff happens. Plot the phase plane including a number of solutions of this system with . You decide what is are good limits for your axes. Describe the solutions in a few words. Do you think that this model gives realistic behavior

Computers and Technology
1 answer:
dezoksy [38]4 years ago
4 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image.

The attached image below describes the inner equilibrium point is a stable node, here it's a center. These are periodic solutions. Populations of the mice and owls are periodic. It describes: when the mice population is lower, the owl population decreases; again the owl is lower so mice got a chance to grow its population; now as sufficient food(mice) is there, the owl population increases; as predator population increases, the prey population decreases;  and this continues as a cycle forever.

So, yes, the model gives a realistic behavior.

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3 years ago
Output a table that show the cube of the numbers 1-15<br> (C++)
Rainbow [258]

Answer:

The c++ program to display cube of numbers from 1 to 15 is given below.

#include <iostream>

using namespace std;

int main() {    

   // variables declared and initialized  

   int num = 15, k, cube;    

   cout << " Cubes of numbers from 1 to 15 are shown below " << endl;    

   for( k = 1; k <= num; k++ )

   {

       // cube is calculated for each value of k and displayed

       cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

return 0;

}

 

OUTPUT

Cubes of numbers from 1 to 15 are shown below  

  1

  8

  27

  64

  125

  216

  343

  512

  729

  1000

  1331

  1728

  2197

  2744

  3375

Explanation:

The variables are declared and initialized for loop, cube and for condition in the loop – k, cube, num respectively.

Inside for loop which executes over k, beginning from 1 to 15, cube of each value of k is calculated and displayed. The loop executes 15 times. Hence, cube for numbers from 1 to 15 is displayed after it is calculated.

   for( k = 1; k <= num; k++ )

   {

      cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

In the first execution of the loop, k is initialized to 1 and variable cube contains cube of 1. Hence, 1 is displayed on the screen.

In the second execution, k is incremented by 1 and holds the value 2. The variable cube contains cube of 2, which is calculated, and 8 gets displayed on the screen.

After each execution of the loop, value of k is incremented.

After 15 executions, value of k is incremented by 1 and k holds the value 16. This new value is greater than num. Hence, the loop terminates.

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Answer:

A = 5 + 1.75r

Explanation:

Amount you have = $5

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Let

r = number of rolls of wrapping paper

A = Total amount earned

A = 5 + 1.75r

Equation that represents the total amount A (in dollars) you have after selling r rolls of wrapping paper is

A = 5 + 1.75r

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Answer:

boolean isEven = false;

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int currentMaxIndex;

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{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

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currentMax = x[j];

currentMaxIndex = j;

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}

x[currentMaxIndex] = x[i];

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}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

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