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Likurg_2 [28]
4 years ago
8

Using the phase plane program described in the introduction, plot the phase plane for the Lotka-Volterra model Here represents t

he population of a prey species, say mice, and is the population of a predator species, for example owls. If there are no owls, then the population of of mice grows exponentially, and if there are no mice, then the owls die off. However if the initial populations are both positive, then interesting stuff happens. Plot the phase plane including a number of solutions of this system with . You decide what is are good limits for your axes. Describe the solutions in a few words. Do you think that this model gives realistic behavior

Computers and Technology
1 answer:
dezoksy [38]4 years ago
4 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image.

The attached image below describes the inner equilibrium point is a stable node, here it's a center. These are periodic solutions. Populations of the mice and owls are periodic. It describes: when the mice population is lower, the owl population decreases; again the owl is lower so mice got a chance to grow its population; now as sufficient food(mice) is there, the owl population increases; as predator population increases, the prey population decreases;  and this continues as a cycle forever.

So, yes, the model gives a realistic behavior.

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Vanyuwa [196]

Answer:

from functools import reduce

def mean(mylist):

   score = reduce(lambda x,y: x + y, mylist)/ len(mylist)

   return score

def median(mylist):

   sorted(mylist)

   list_len = len(mylist) % 2

   i = round(len(mylist)/2)

   x = len(mylist)//2

   if list_len == 0:

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   else:

       median = mylist[i]

   return median

def mode(mylist):

   unique = set(mylist)

   unique = list(unique)

   collector = [mylist.count(key) for key in unique]

   maxi = max(collector)

   loc = collector.index(maxi)

   return unique[loc]

def main():

   scores = input( 'Enter list of numbers: ').split(",")

   scores = [int(score) for score in scores]

   

   operation = input('Enter operation: ')

   operator = ['mean', 'median', 'mode']

   

   for x in iter(list, 0):

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           break

       print("Invalid operation: ")

       operation = input('Enter operation')

   

   index_loc = operator.index(operation)

   

   if index_loc == 0:

       return mean(scores)

   elif index_loc == 1:

       return median(scores)

       #return np.median(scores)  can be used of the defined function

   elif index_loc == 2:

       #return stats.mode(scores)[0]  can be used of the defined function

       return mode(scores)

print( main( ) )

Explanation:

The main python function calls conditionally three statistical functions namely mean, median and mode. It prompts for user input for a list of integer numbers and a function name name to return the corresponding result.

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the answer is True

i hope it will help you

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