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3 years ago

Synonyms and antonyms!

Mathematics

2 answers:

KIM [24]3 years ago

7 0

3 re·lieve

/rəˈlēv/

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verb

cause (pain, distress, or difficulty) to become less severe or serious.

synonyms:alleviate, mitigate, assuage, allay, soothe, soften, palliate, appease, ease, dull,

4 loll

/läl/

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verb

sit, lie, or stand in a lazy, relaxed way.

synonyms:lounge, sprawl, drape

5coax1

/kōks/

verb

gently and persistently persuade (someone) to do something.

synonyms:persuade, wheedle, cajole, talk into something, get round, prevail on, beguile, flatter, seduce, lure, entice, tempt, inveigle, woo, maneuver

dem82 [27]3 years ago

3 0

Answer:

3. relieve and alleviate (S)

4. loll and sprawl (S)

5. coax and cajole (S)

Hope this helps! :)

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In the image it appears everything

rosijanka [135]

X = -3 it's practically the y intercept in which x is equals 0

4 0

2 years ago

Read 2 more answers

Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).

fiasKO [112]

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

$y = 6(7x + 9)(8x - 3)$

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

$7x + 9 = 0$

$7x = -9$

$x = -\frac{9}{7}$

So (-9/7, 0) is a zero of the quadratic function.

The other is:

$8x - 3 = 0$

$8x = 3$

$x = \frac{3}{8}$

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.

6 0

2 years ago

The graph below shows the value of Edna's profits f(t), in dollars, after t months:

umka21 [38]

Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
$x=6$
$x-6=0$
$x=18$
$x-18=0$

$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the <span>9th month
</span> $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>