Let c = number of children
Let a = number of adults
5a + 2c > 3350
<u>(a) Construct a 95% confidence interval for the difference between the average number of intrusion attempts per day before and after the change of firewall setting (assume equal variance)</u>
Answer:
Nearest cent- $1.43
Step-by-step explanation:
14.25x0.10=1.425