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Irina18 [472]
3 years ago
11

Which is an example of perpendicular lines?

Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0
The answer would be choice C. 
Perpendicular lines cross each other and form a right angle as you can see marked in the third picture.
Rzqust [24]3 years ago
8 0
It's C. Perpendicular lines have to cross each other
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-3x - y = 0 and -8x +5y=7
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-23x = 7

Step-by-step explanation:

-3x - y =0

×5. ×5 ×5

-15x -5y = 0

-8x +5y = 7

-15x -5y -0

-23x = 7

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They leave it on the moon.
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KatRina [158]

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720

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Braceleftzf y = 8/7 x − 2/3 <br> 8/3 x + y = 5/9
givi [52]

Answer:

  (x, y) = (77/240, -3/10)

Step-by-step explanation:

It is convenient to write the equations in standard form.

Multiplying the first equation by 21 gives ...

  21y = 24x -14

Multiplying the second equation by 8 gives ...

  24x +9y = 5

Then the system of equations in standard form is ...

  • 24x -21y = 14
  • 24x +9y = 5

Subtracting the first from the second, we get ...

  (24x +9y) -(24x -21y) = (5) -(14)

  30y = -9

  y = -9/30 = -3/10

Substituting this into the second equation, we have ...

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  x = 7.7/24 = 77/240

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7 0
3 years ago
Need help with problems 16 and 17, please? I'll do brainiac
natali 33 [55]

Answer: 16) y=-0.5x+3 and 17) y=2x-3

Step-by-step explanation:

16: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Since y=3 at x=0, the y-intercept is (0,3), and b=3.

Slope=\frac{y_{2} -y_{1} }{x_{2}-x_{1}  } where (x_{1} ,y_{1}) and (x_{2} ,y_{2}) are two points on the line. Choose (0,3) and (2,2):

Slope=\frac{2-3}{2-0}=-0.5

Plug m=-0.5 and b=3 into y=mx+b:

y=-0.5x+3

17: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Because y=-3 at x=0, the y-intercept is (0,-3), and b=-3.

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Slope=\frac{-3-(-1)}{0-1}=\frac{-2}{-1}=2

Plug m=2 and b=-3 into y=mx+b:

y=2x-3

5 0
3 years ago
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