Use the substitution method to solve the system of equations.
1 answer:
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Answer:
34.01% probability that his score is at least 532.1.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If 1 of the men is randomly selected, find the probability that his score is at least 532.1.
This is 1 subtracted by the pvalue of Z when X = 532.1. So
has a pvalue of 0.6591
1 - 0.6591 = 0.3409
34.01% probability that his score is at least 532.1.
Answer:
Jillian is Incorrect as fraction can never be balanced based on numerator or denominator.
Step-by-step explanation:
Given:
Measure of ribbon Kiara has =
Measure of ribbon Jillian has =
Now given:
Jillian says their ribbons are equal in length because her numerator is one more than kiara's and her denominator is one less, therefore balancing the two fractions.
we need to find whether statement is correct or not.
First we will find the decimal value of the given fraction's
can rewritten as
Measure of ribbon Kiara has = 0.25 inch
can be Rewritten as
Measure of ribbon Jillian has = 0.67 inch
Now we can see that;
0.67 inch is greater than 0.25 inch.
Hence we can say that ribbons are not in equal length.
Also the fraction can never be balanced by decreasing or increasing the numerator or denominator.