F(x)=x^2 +8x
f(d-3) basically what we get from this is that the x value is d-3
to find f(d-3) simply plug in d-3 for every x
f(d-3)=(d-3)^2 + 8(d-3)
that would be one form of the answer, but we can also continue multiplying it out
f(d-3)= d^2-6d+9+8d-24
add like terms
f(d-3)=d^2+2d-15
have a nice day and i hope this helps :)
3(-3 + 5x) -1 (4 - 4x)
Simplify each term by first using the distributive property with each set of parenthesis:
3*-3 + 3*5x - 1*4 -1* -4x
Now do the multiplications:
-9 + 15x -4 + 4x
Combine like terms
15x +4x - 9 -4
19x - 13
I think it’s the second one
-4/3x + 1/6 < 7/9
-4/3x < 7/9 - 1/6 7/9 - 1/6 = 42/54 - 9/54 = 33/54 = 11/18
-4/3x < 11/18
-x < 11/18 ÷ 4/3 11/18 ÷ 4/3 = 11/24
-x < 11/24
x > -11/24
