Answer:
x = 13sqrt(3) ft = 22.5 ft
y = 13 ft
Step-by-step explanation:
The triangle is a 30-60-90 right triangle.
The ratio of the lengths of the sides is
short leg : long leg : hypotenuse = 1 : sqrt(3) : 2
From the ratio above we see that the hypotenuse is twice the short leg.
The long leg is sqrt(3) times the short leg.
y = short leg
x = long leg
26 ft = hypotenuse
y = 26 ft/2 = 13 ft
x = 13 ft * sqrt(3) = 13sqrt(3) ft = 22.5 ft
I don't get it a all I tried fr
The definition of an example of expression is a frequently Answer:
Step-by-step explanation:The definition of an example of expression is a frequently used word or phrase or it is a way to convey your thoughts, feelings or emotions. An example of an expression is the phrase "a penny saved is a penny earned." An example of an expression is a smile. A facial aspect or a look that conveys a special feeling used word or phrase or it is a way to convey your thoughts, feelings or emotions.
equations...There are three major forms of linear equations: point-slope form, standard form, and slope-intercept form
Answers these are 5..
5 Examples
Noun Phrase; Friday became a cool, wet afternoon.
Verb Phrase; Mary might have been waiting outside for you..
Gerund Phrase; Eating ice cream on a hot day can be a good way to cool off.
Infinitive Phrase; She helped to build the roof.
Prepositional Phrase; In the kitchen, you will find my mom.
Answer:
The distance between L and the line KH and HF is;
The value of y is;
Explanation:
Given the figure in the attached image;
From the image;
So, the distance between L and the line KH and HF is;
Also, the triangles KHL and FHL are congruent.
So, the angles KHL and FHL are congruent.
Substituting the expressions;
Therefore, the value of y is;
Answer:
Step-by-step explanation:
With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0
As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.
At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)
we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.
we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔ m.
It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m
