Question

Find the area of a rectangle whose vertices are (2,2),(-3,2),(2,8), and (-3,8)

Answer 1

Answer:

Area of rectangle = 30 units

Step-by-step explanation:

vertices are (2,2),(-3,2),(2,8), and (-3,8)

Let find the distance between (2,2)  and (2,8). because they have same x values. that would be our width

distance = $\sqrt{(x_2-x_1)^2 + (y_2-y_2)^2}$

D = $\sqrt{(2-2)^2 + (8-2)^2}=\sqrt(6^2) = 6$

Width = 6

Now we find distance between (2,2) and (-3,2) because they have same y values, that would be our length

distance = $\sqrt{(x_2-x_1)^2 + (y_2-y_2)^2}$

D = $\sqrt{(-3-2)^2 + (2-2)^2}=\sqrt(-5^2) = \sqrt(25)= 5$

length = 5

Area of rectangle = length * width = 5*6 = 30