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WARRIOR [948]
3 years ago
10

2. What fractional part of the quadrilateral is not shaded? ​

Mathematics
2 answers:
Alla [95]3 years ago
5 0

Answer:

plz show the pic so I can understand

Nikitich [7]3 years ago
5 0
Can u please put a picture or more specific
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I don’t understand how to do this without plugging in numbers or using calculus. Please help. I’m studying for the SAT and I onl
Svetllana [295]

Step-by-step explanation:

Recall that for a quadratic equation y = ax² + bx + c in the X-Y plane, the x-location of the vertex (i.e maximum or minimum point) is given by

x @vertex = -b/2a

in this case your quadratic equation is

h = 4 + 20t - 5t²   (rearranging in the form y = ax² + bx + c )

h = - 5t² + 20t + 4

hence a= -5, b = 20 and c = 4

applying the formula for vertex

t @ vertex = -b  /2a = -(20) / (2)(-5) = -20/-10 = 2

therefore t = 2

8 0
3 years ago
Order the following from least to greatest: 14 -6, 0, 8, 3.4, -8, 2​
Leto [7]

Answer:

-6. -8 0 3.4 6 8 14

Step-by-step explanation:

I think I am correct

5 0
3 years ago
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How many grams are in 2000mg
Aleonysh [2.5K]

Answer:

2g :)

Step-by-step explanation:

6 0
4 years ago
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I’m stuck on this question please help
FrozenT [24]

a = 8

b = 6

c = 12

hope this helps!

4 0
3 years ago
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How much of 30% HCI and 45% HCI would be needed to mix and produce 50 liters of 35% HCI
VladimirAG [237]

Answer:

  • 33 1/3 liters of 30%
  • 16 2/3 liters of 45%

Step-by-step explanation:

Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...

  0.45x +0.30(50 -x) = 0.35(50)

  0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)

  x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl

33  1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.

_____

<em>Comment on the solution</em>

You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...

  (mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3

5 0
4 years ago
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