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taurus [48]
4 years ago
13

I need help with this

Mathematics
1 answer:
tekilochka [14]4 years ago
7 0
You have to find the length of the side. Look it up on Kahn academy. It really helps. Look up: how to do perpendicular bisector theorem. I hope this helped :)
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Please help I’m super confused .....................
Maru [420]

Answer:

D

Step-by-step explanation:

Using the sentences "One thing parents should not be worried about vaccinating their kids; still, the debate rages on," and the sentence "The real culprit undermining the public's safety is a <u><em>baseless</em></u> claim that vaccinations lead to autism." Using the fact that it is baseless, we can deduce that the author thinks it is not something to worry about. This means that we can rule out B and C. Also, A is not correct because the passage rarely mentions about this, so the answer is D.

3 0
3 years ago
In a plane, the lengths of line segments AB, BC, and CD are 3, 5, and 1. If m represents the greatest possible length of line se
coldgirl [10]
8? I think

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4 0
2 years ago
A rugby player passes the ball 7.75 m across the field, where it is caught at the same height as it left his hand. At what angle
prisoha [69]

<u>Answer-</u>

<em>At 15.91° the ball was thrown.</em>

<u>Solution-</u>

<em>In the question it is given that the ball was released and caught from the same height.</em>

We know that,

R=\frac{u^{2}\sin 2\Theta}{g}

Where,

R = Range of the projectile = 7.75 m,

u = Initial speed = 12 m/s

θ = Angle at which it was released

g = Acceleration due to gravity = 9.8 m/s²

Putting all the values,

\Rightarrow 7.75 = \frac{12^{2}\sin 2\Theta}{9.8}

\Rightarrow \sin 2\Theta=\frac{7.75 \times 9.8}{144} =0.5274

\Rightarrow 2\theta=\sin^{-1} 0.5274=31.83 \ or \ 148.17

\Rightarrow \theta=\frac{31.83}{2} \ or \ \frac{148.17}{2} =15.91 \ or \ 74.08

\Rightarrow \theta=15.91^{\circ} \ (smaller \ angle)

3 0
3 years ago
Read 2 more answers
Select the two values of x that are roots of this equation.<br> x^2+1=5x <br> *APEX
snow_lady [41]

Answer:

\large\boxed{B.\ x=\dfrac{5+\sqrt{21}}{2},\ C.\ x=\dfrac{5-\sqrt{21}}{2}}

Step-by-step explanation:

\text{Use the quadratic formula:}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\================================\\\\\text{We have}:\\\\x^2+1=5x\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\x^2-5x+1=0\\\\a=1,\ b=-5,\ c=1\\\\b^2-4ac=(-5)^2-4(1)(1)=25-4=21\\\\x=\dfrac{-(-5)\pm\sqrt{21}}{2(1)}=\dfrac{5\pm\sqrt{21}}{2}

6 0
3 years ago
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2+2=<br> A.4<br> B.2 <br> C.6<br> D. none of the above
expeople1 [14]

Answer:

A. 4

Step-by-step explanation:

lol

8 0
3 years ago
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