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4 years ago

I need help with this

Mathematics

1 answer:

tekilochka [14]4 years ago

7 0

You have to find the length of the side. Look it up on Kahn academy. It really helps. Look up: how to do perpendicular bisector theorem. I hope this helped :)

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vector v has a horizontal vector component with magnitude 19 and a vertical vector component with magnitude 35. what is the acut

vladimir2022 [97]

9514 1404 393

Answer:

61.5°

Step-by-step explanation:

The tangent relation is useful here. The angle is opposite the vertical side and adjacent to the horizontal side of the right triangle.

Tan = Opposite/Adjacent

tan(α) = 35/19

α = arctan(35/19) ≈ 61.5°

The angle made by <em>v</em> and the positive x-axis is 61.5°.

4 0

3 years ago

I dont know how to do thiss can someone help

lesantik [10]

Step-by-step explanation:

REO=RBO=67

BOR=ERO=91

REB=REO-BE0=67-32=35

RYE=180-ERO-REB=180-91-35=54

3 0

3 years ago

Select the correct answer. The radius of a nitrogen atom is 5. 6 × 10-11 meters, and the radius of a beryllium atom is 1. 12 × 1

Grace [21]

A negative exponent means the number of the exponent divide by the number. The the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.

Given information-

The radius of a nitrogen atom is $5.6\times10^{-11}$ meters.

The radius of a beryllium atom is $1.12 \times10^{-10}$ meters

<h3>Negative exponents</h3>

A negative exponent means the number of the exponent divide by the number.

As the radius of the nitrogen atom is $5.6\times10^{-11}$ meters. Convert it in the power of negative exponent of 10.

Let the radius of the nitrogen is $r$ mm. Thus,

$r=5.6\times 10^{-11}\\
r=5.6\times 10^{-10-1}\\
r=5.6\times 10^{-10}\times10^{-1}\\
r=\dfrac{5.6\times 10^{-10}}{10} \\
r=0.56\times 10^{-10}$

Now the base of the exponents of both the atoms are same. As the radius of the nitrogen atom is $0.56\times 10^{-10}$ meters and the radius of the beryllium atom is $1.12 \times10^{-10}$ . Thus the radius of beryllium atom is larger.

To calculate how many times, the radius of beryllium atom should be divided by the radius of a nitrogen atom. Thus,

$=\dfrac{1.12\times10^{-10}}{0.56\times10^{-10}} \\
=2$

Thus the the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.

Learn more about the negative exponents here;

https://brainly.in/question/1221452

7 0

3 years ago

Triangle abc has side lengths ab = 65, bc = 33, and ac = 56. find the radius of the circle tangent to side ac and bc and to the

lara [203]

The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.

r= 24.

<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>

Generally, the equation for side lengths AB is mathematically given as

Triangle ABC has side lengths

Where

AB = 65,
BC = 33,
AC = 56.

Hence

r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),

r = 89 − 65

r= 24.

In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.

r= 24.