Answer:
The answer is 54.4
Step-by-step explanation:
Answer: 729
Step-by-step explanation:
Move items with negative exponents from numerator to denominator or vice versa and change sign of exponent. Factorize composite numbers, say 10^3 = 2^3 × 5^3 and 81 = 3^4. Combine factors with same base, adding exponents. Cancel factors appearing in both numerator and denominator, subtracting exponents.
5^-3×6^-5×81×4/(3^-7×10^-3)
= 3^7×10^3×81×4/(5^3×6^5)
= 3^7×2^3×5^3×3^4×2^2/(5^3×2^5×3^5)
= 2^5×3^11×5^3/(2^5×3^5×5^3)
= 3^6
= 729
Answer:
I know an app its called math-way its really good for math
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have the following system
![\left[\begin{matrix} 4 & -2 \\ 2 & 1 \end{matrix}\right]x =\left[\begin{matrix} 8 \\ 2 \end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Bmatrix%7D%204%20%26%20-2%20%5C%5C%202%20%26%201%20%5Cend%7Bmatrix%7D%5Cright%5Dx%20%3D%5Cleft%5B%5Cbegin%7Bmatrix%7D%208%20%5C%5C%202%20%5Cend%7Bmatrix%7D%5Cright%5D)
The number of solutions depend on the determinant of the matrix of the system. If the determinant is different from 0, then it has one unique solution, if it 0 then it has infinite solutions.
Note that the determinant of a matrix
![\left[\begin{matrix} a & b \\ c & d \end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Bmatrix%7D%20a%20%26%20b%20%5C%5C%20c%20%26%20d%20%5Cend%7Bmatrix%7D%5Cright%5D)
is ad-bc. So in our case we have 4*1-(-2)*2 = 8 which is not 0. Then the system has an unique solution.
