Embryophyta is a clade within the Phragmoplastophyta, a larger clade that also includes several green algae groups. Embryophytes are the plants growing on land which include hornworts, liverworts, gymnosperms, flowering plants etc while green algae mostly thrive in aquatic environment.
The conduction of water requires vascular tissue called xylem. In green algae, it is not necessary to have water conducting tissue as the entire body is in contact with water. However in embryophytes, having a vascular tissue is an adaptation that ensures to provide water to the higher parts of the plant which is not directly in contact with the soil.
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Answer:
D. Plasma membrane.
Explanation:
The structure which is present in both of those cells is:
D. Plasma membrane.
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Given data:
● Angular velocity of the turntable ω = 33 rev/min
Therefore,
ω = 33 rev/min
ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s
● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m
● μs = the coefficient of static friction
Section a:
The seed is undergoes circular motion and it is been effected by centripetal acceleration.
ac = rω^2
ac = 0.078 × 3.45^2
ac = 0.9284 m/s^2
Therefore,
the centripetal acceleration of the seed is 9.274 m/s^2
Section b:
If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.
Centripetal Force = Frictional Force
mrω^2 = μsmg
μs = rω^2 /g
μs = 0.078 × 3.45^2
------------
9.81
μs = 0.09464
Thus,
the coefficient of static friction is 0.09464.