25-3=22
22/2 = 11
John made 14 free throws while Jose made 11.
Answer:
A and Care parallel, B and D are parallel
Step-by-step explanation:
It’s C
have an awesome day:)
To feel good about your body oh to stay healthy is downs
Answer:
![\sin L = \frac{3}{5}](https://tex.z-dn.net/?f=%5Csin%20L%20%3D%20%5Cfrac%7B3%7D%7B5%7D)
![\tan N = \frac{4}{3}](https://tex.z-dn.net/?f=%5Ctan%20N%20%3D%20%5Cfrac%7B4%7D%7B3%7D)
![\cos L = \frac{4}{5}](https://tex.z-dn.net/?f=%5Ccos%20L%20%3D%20%5Cfrac%7B4%7D%7B5%7D)
![\sin N = \frac{4}{5}](https://tex.z-dn.net/?f=%5Csin%20N%20%3D%20%5Cfrac%7B4%7D%7B5%7D)
Step-by-step explanation:
Given
The above triangle
First, we calculate the length LM using Pythagoras theorem.
![LN^2 = LM^2 + MN^2](https://tex.z-dn.net/?f=LN%5E2%20%3D%20LM%5E2%20%2B%20MN%5E2)
![10^2 = LM^2 + 6^2](https://tex.z-dn.net/?f=10%5E2%20%3D%20LM%5E2%20%2B%206%5E2)
![100 = LM^2 + 36](https://tex.z-dn.net/?f=100%20%3D%20LM%5E2%20%2B%2036)
Collect like terms
![LM^2 = 100 - 36](https://tex.z-dn.net/?f=LM%5E2%20%3D%20100%20-%2036)
![LM^2 = 64](https://tex.z-dn.net/?f=LM%5E2%20%3D%2064)
Take positive square root
![LM=8](https://tex.z-dn.net/?f=LM%3D8)
Solving (a): Sin L
![\sin L = \frac{Opposite}{Hypotenuse}](https://tex.z-dn.net/?f=%5Csin%20L%20%3D%20%5Cfrac%7BOpposite%7D%7BHypotenuse%7D)
![\sin L = \frac{MN}{LN}](https://tex.z-dn.net/?f=%5Csin%20L%20%3D%20%5Cfrac%7BMN%7D%7BLN%7D)
![\sin L = \frac{6}{10}](https://tex.z-dn.net/?f=%5Csin%20L%20%3D%20%5Cfrac%7B6%7D%7B10%7D)
Simplify
![\sin L = \frac{3}{5}](https://tex.z-dn.net/?f=%5Csin%20L%20%3D%20%5Cfrac%7B3%7D%7B5%7D)
Solving (b): tan N
![\tan N = \frac{Opposite}{Adjacent}](https://tex.z-dn.net/?f=%5Ctan%20N%20%3D%20%5Cfrac%7BOpposite%7D%7BAdjacent%7D)
![\tan N = \frac{LM}{MN}](https://tex.z-dn.net/?f=%5Ctan%20N%20%3D%20%5Cfrac%7BLM%7D%7BMN%7D)
![\tan N = \frac{8}{6}](https://tex.z-dn.net/?f=%5Ctan%20N%20%3D%20%5Cfrac%7B8%7D%7B6%7D)
Simplify
![\tan N = \frac{4}{3}](https://tex.z-dn.net/?f=%5Ctan%20N%20%3D%20%5Cfrac%7B4%7D%7B3%7D)
Solving (c): cos L
This calculated as:
![\cos L = \frac{Adjacent}{Hypotenuse}](https://tex.z-dn.net/?f=%5Ccos%20L%20%3D%20%5Cfrac%7BAdjacent%7D%7BHypotenuse%7D)
![\cos L = \frac{LM}{LN}](https://tex.z-dn.net/?f=%5Ccos%20L%20%3D%20%5Cfrac%7BLM%7D%7BLN%7D)
![\cos L = \frac{8}{10}](https://tex.z-dn.net/?f=%5Ccos%20L%20%3D%20%5Cfrac%7B8%7D%7B10%7D)
Simplify
![\cos L = \frac{4}{5}](https://tex.z-dn.net/?f=%5Ccos%20L%20%3D%20%5Cfrac%7B4%7D%7B5%7D)
Solving (d): sin N
This is calculated using:
If ![a + b = 90](https://tex.z-dn.net/?f=a%20%2B%20b%20%3D%2090)
Then: ![\sin a = \cos b](https://tex.z-dn.net/?f=%5Csin%20a%20%3D%20%5Ccos%20b)
So:
![\sin N = \cos L](https://tex.z-dn.net/?f=%5Csin%20N%20%3D%20%5Ccos%20L)
![\sin N = \frac{4}{5}](https://tex.z-dn.net/?f=%5Csin%20N%20%3D%20%5Cfrac%7B4%7D%7B5%7D)