Step-by-step explanation:
you multiply 1/6 to each number in the brackets
The cube root of 2 is irrational. The proof that the square root of 2 is irrational may be used, with only slight modification. Assume the cube root of 2 is rational. Then, it may be written as a/b, where a and b are integers with no common factors. (This is possible for all nonzero rational numbers). Since a/b is the cube root of 2, its cube must equal 2. That is, (a/b)3 = 2 a3/b3 = 2 a3 = 2b3. The right side is even, so the left side must be even also, thatis, a3 is even. Since a3 is even, a is also even (because the cube of an odd number is always odd). Since a is even, there exists an integer c such that a = 2c. Now, (2c)3 = 2b3 8c3 = 2b3 4c3 = b3. The left side is now even, so the right side must be even too. The product of two odd numbers is always odd, so b3 cannot be odd; it must be even. Therefore b is even as well. Since a and b are both even, the fraction a/b is not in lowest terms, thus contradicting our initial assumption. Since the initial assumption cannot have been true, it must <span>be false, and the cube root of 2 is irrational.
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Answer:
B
Step-by-step explanation:
Answer:
217.04 cm²
Step-by-step explanation:
We should first calculate the area of the rectangle:
A= 14*21 =294cm²
then we should substract the area of the half-cercle :
A'= (7²*π)/2=76.96 cm²
then the area of the shaded area is :
A"= 294-76.96= 217.04 cm²
Answer:
Step-by-step explanation:
Answer
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