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postnew [5]
3 years ago
6

How to factor x^2-49y^2

Mathematics
2 answers:
marishachu [46]3 years ago
8 0
x^2-49y^2=x^2-(7y)^2=(x-7y)(x+7y)\\\\\\a^2-b^2=(a-b)(a+b)
Zigmanuir [339]3 years ago
3 0
X^2-49y^2 = (x-7y)(x+7y)
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Im broke have this but like whats 24X58-9=<br><br><br><br> 800x24=?
Mekhanik [1.2K]

Answer:

24X58-9=1,383

800x24=19,200

Step-by-step explanation:

24x58=(24x8)+(24x50)

24x8=160+32=192

24x50=200+1,000=1,200

192+1,200=1,392-9=1,383

800x24=3,200+16,000=19,200

4 0
2 years ago
Unit price $12 for 150lb bag
makvit [3.9K]

Answer:

For $1 its 12.5lbs

Step-by-step explanation:

6 0
3 years ago
If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?
Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

g(x)=4x^2-16

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:

\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)

Therefore, If we shift the red graph 9 units to the right and 1 down, our new function (let's call it h(x)) will be:

h(x)=4\left(x-9\right)^{2}-16-1 \\ \\ Simplifying: \\ \\ h(x)=4\left(x-9\right)^{2}-17

This graph is the blue graph below. Let's verify the transformation taking the vertex of the red graph:

(0,-16)

By translating the 9 units to the right and 1 down the vertex is also translated by the same rule, so:

New \ vertex: \\ \\ (0+9,-16-1) \\ \\ (9,-17)

<h2>Learn more:</h2>

Cubic function: brainly.com/question/13773618#

#LearnWithBrainly

5 0
3 years ago
What is the measure (in radians) of central angle &amp; in the circle below?
MA_775_DIABLO [31]

Answer:

7pi/6

Step-by-step explanation:

Using the formula for arc length in radians, we get:

  1. 14pi = 12(theta)
  2. theta = 7pi/6 [divide both sides by 12]
8 0
2 years ago
Can 12(x^3+y^2)+6(y^2+1) be the factored form of 12x^3+18y^2+6?
Misha Larkins [42]

Answer:

YES

Step-by-step explanation:

So how you can figure this out is you do the Distributive Property.

So it will be 12x^3+12y^2+6y^2+6.

The next thing you have to do is add together the ones that are similar which is 12y^2+6y^2 to get 18y^2.

Your answer is 12x^3+18y^2+6. So YES it can be factored into that form.

4 0
3 years ago
Read 2 more answers
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