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3 years ago

How to factor x^2-49y^2

Mathematics

2 answers:

marishachu [46]3 years ago

8 0

$x^2-49y^2=x^2-(7y)^2=(x-7y)(x+7y)\\\\\\a^2-b^2=(a-b)(a+b)$

Zigmanuir [339]3 years ago

3 0

X^2-49y^2 = (x-7y)(x+7y)

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If 3 units equal 3 feet, what is the value of 1 unit?

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Answer:1 foot

If 3 units equal 3 feet, what is the value of 1 unit?

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3 years ago

Which line is the line of reflection? A. a B. b C. c D. d

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The line of reflection is b

You can see it much easier if take away all the clutter. Redraw the diagram and take way a d and especially c.

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Does 2, 2, √4 make a right triangle

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Answer:

No it can'tright angle triangle

Step-by-step explanation:

2, 2, √4 can't make a right triangle

By Pythagoras theorem the square of two sides equal to the third side of the triangle.

2^2+2^2=(√4)^2

4+4=4

8 is not equal to 4 so it not make right angle triangle.

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3 years ago

NEED ANSWERS NOW!! (Reward) brainlest and pointsss

geniusboy [140]

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square.

Given

f(x) = - 0.6x² + 4.2x + 240 ← factor out - 0.6 from the first 2 terms

= - 0.6(x² - 7x) + 240

To complete the square

add/ subtract ( half the coefficient of the x- term)² to x² - 7x

f(x) = - 0.6(x² + 2(- 3.5)x + 12.25 - 12.25 ) + 240

= - 0.6 (x - 3.5)² + 7.35 + 240

= - 0.6(x - 3.5)² + 247.35

with vertex = (3.5, 247.35 )

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3 years ago

Karma is building a rectangular table with an area of 18,000 cm?. He wants to put wood trim around the four edges. What is the s

jok3333 [9.3K]

The shortest length is given by the function for the perimeter of the

rectangular table.

The shortest length of trim he could use is 536.66 cm

<h3>Method used for finding the shortest length of trim</h3>

The given parameter;

Area of the rectangular table Karma is building, A = 18,000 cm²

Required:

The shortest length of trim he could use which he wants to put around the four edges.

Solution:

Let l represent the length of the table, and let w represent the width, therefore;

Perimeter of the table, P = 2·l + 2·w

Area, A = l × w

Which gives;

18,000 = l × w

$l = \dfrac{18,000}{w}$

Which gives;

$P = 2 \cdot \dfrac{18,000}{w} + 2 \cdot w$

At the minimum point, we have;

$\dfrac{d}{dw} P = \dfrac{d}{dw} \left(2 \cdot \dfrac{18,000}{w} + 2 \cdot w\right)= \mathbf{\dfrac{2 \cdot w^2 - 36,000}{w^2} }= 0$

Which gives;

2·w² - 36,000 = w² × 0 = 0

2·w² = 36,000

$w^2 = \dfrac{36,000}{2} = 18,000$

The width of the rectangular table, w = √(18,000)

$Length \ of \ the \ table\ l = \dfrac{18,000}{\sqrt{18,000} } = \sqrt{18,000}$

Therefore;

The perimeter of the table, P ≈ 2 × √(18,000) + 2 × √(18,000) ≈ 536.656

The length of trim required = The perimeter of the rectangular table, P

Therefore;

The shortest length of the trim he could use, given to the nearest hundredth is 536.66 cm

Learn more about area and perimeter of a figure here:

brainly.com/question/9135929

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3 years ago