We are given that a sample survey interviews SRS of 500 female college students and 550 male college students. And Researchers want to determine whether there is a difference in the proportion of male and female college students who worked for pay last summer.

In all, 410 of the females and 484 of the males say they worked for pay last summer.

From this, Null Hypothesis, $H_0$ : $p_1 = p_2$ {means proportion of male and female college students who worked for pay last summer are same}

Alternate Hypothesis, $H_1$ : $p_1\neq p_2$ {means there is a difference in the proportion of male and female college students who worked for pay last summer}

Now, since we know that results were statistically significant at the 1% level.

So, if p-value is less than the significance level ⇒ we will reject $H_0$

if p-value is more than the significance level ⇒ we will not reject $H_0$

From the options given it is sure that P-value is less than 1%,i.e.;

<em>P-value is less than the significance level, so we will reject null hypothesis and conclude that there is convincing evidence that the proportion of all male college students in the study who worked for pay last summer is different from the proportion of all female college students in the study who worked for pay last summer. </em>

Also, option (d) and (e) are same in my opinion.

4 0

3 years ago

Write and evaluate the expression. Then, complete the statements. Ten less than the quotient of thirty and a number Evaluate whe

Artyom0805 [142]

Answer:

expression: (30/t) - 10

evaluation: 30/2 - 10 = 5

Step-by-step explanation:

8 0

3 years ago