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Keith_Richards [23]
3 years ago
15

Use the formula to find the standard error of the distribution of differences in sample means, x¯1-x¯2 . Samples of size 110 fro

m Population 1 with mean 94 and standard deviation 14 and samples of size 85 from Population 2 with mean 72 and standard deviation 15 Round your answer for the standard error to
Mathematics
1 answer:
Volgvan3 years ago
7 0

Answer:

2.104

Step-by-step explanation:

Data provided in the question:

For sample 1,

n₁ = 110

μ₁ = 94

s₁ = 14

For sample 2,

n₂ = 85

μ₂ = 72

s₂ = 15

Now,

Standard error = \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

or

Standard error = \sqrt{\frac{14^2}{110}+\frac{15^2}{85}}

or

Standard error = √4.43

or

Standard error = 2.104

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Yuki888 [10]

Answer:

0.5962

Step-by-step explanation:

Given that :

p = 61% = 0.61

q = 1 - p = 1 - 0.61 = 0.39

n = 154 ; x = 93

Using the binomial probability formula :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

P(x>=93) = p(x=93)+p(x=94)+...+p(x=n)

P(x>= 93) = 0.59619

P(x>= 93) = 0.5962

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3 years ago
If p(x) = 2x2 – 4x and q(x) = x – 3, what is mc007-1.jpg? 2x2 – 4x + 12 2x2 – 16x + 18 2x2 – 16x + 30 2x2 – 16x + 15
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To find the answer, we plug q(x) into p(x):
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The third option is correct.

3 0
4 years ago
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