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3 years ago

I really don't get how to do this can someone answer the half page for me?

Mathematics

1 answer:

Lorico [155]3 years ago

5 0

Just multiply each sides by each other

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How do I find angle a?

vfiekz [6]

The slope of the line is 2/3, so the angle is arctan(2/3) ≈ 33.69°.

8 0

2 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

2 years ago

A sandbox has a volume of 648 cubic feet. what is the volume, in cubic yards, of the sandbox?

Eduardwww [97]

We know that

1 cubic yards equals to--------------> 27 cubic feet
then
I apply a rule of three
if 1 cubic yards ------------------- 27 ft³
X----------------------------------> 648 ft³
X=648/27=24 cubic yards

the answer is 24 cubic yards

6 0

3 years ago

I’m really confused please help

sveticcg [70]

Answer: probly d

Step-by-step explanation:

a ,b ,and c are subtracting makeing it hard top get something that was not in the problem

6 0

2 years ago

What is the radius for the circle given by the equation x^2+(y -3)^2 = 21

MatroZZZ [7]

$\bf\textit{equation of a circle}\\\\(x- h)^2+(y- k)^2= r^2\qquadcenter~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquadradius=\stackrel{}{ r}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\x^2+(y-3)^2=21\implies (x-0)^2+(y-3)^2=(\sqrt{21})^2\qquad \begin{cases}center~(0,3)\\r=\sqrt{21}\end{cases}\\\\\\r\approx 4.58257569495584000659\implies r = \stackrel{\textit{rounded up}}{4.583}$

3 0

3 years ago

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