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Olin [163]
3 years ago
11

I really don't get how to do this can someone answer the half page for me?

Mathematics
1 answer:
Lorico [155]3 years ago
5 0
Just multiply each sides by each other
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The heights of Karina, Miya and Clint were 155cm, 158cm, and 161cm respectively. What is the height of Roger if the mean of all
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Answer:

refrase the question

Step-by-step explanation:

7 0
2 years ago
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Help me with this!!!!
andre [41]

Answer: -93.5

Step-by-step explanation:

Average of the two -94+-93/2= -93.5 so thats the midpoint

4 0
3 years ago
The price of a cup of coffee was $2.65 yesterday. today, the price fell to $2.50 . find the percentage decrease. round your answ
sergejj [24]
We must find the difference between prices. $2.65 - $2.50 = $0.15. Now we need to calculate what percent $0.15 is of $2.65. It is 5.7%! The price decreased, so it is a 5.7% decrease!
8 0
3 years ago
Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

since cosec x = 1/sinx

1/sinx = 4

sinx = 1/4

From SOH, CAH TOA

sinθ = opposite/hypotenuse

from sinx = 1/4

opposite = 1 and hypotenuse = 4

to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

adj = √15

cosx = adj/hyp = √15/4

tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

sin2x = 2(1/4)(√15/4)

sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

cos2x = 7/8

for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

5 0
3 years ago
Find a cubic polynomial in standard form with real​ coefficients, having the zeros 4 and 5i. Let the leading coefficient be 1.
SCORPION-xisa [38]
If one of our zeros is 4, then the factor is x-4.  If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i.  So our 3 factors are (x-4)(x+5i)(x-5i).  We will FOIL out these factors to get the polynomial.  Let's start with the ones that contain the imaginary numbers.  Doing that mutliplication we get x^2-25i^2.  i^2 is equal to -1, so what that expression simplifies down to is x^{2} +25.  Now we will multiply in that last factor of (x-4):  (x^2+25)(x-4).  FOILing out we have x^3-4x^2+25x-100.  There you go!
3 0
3 years ago
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