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Shkiper50 [21]
2 years ago
14

A movie rental club charges a one time fee of $25 to join and $2 for every movie rented which equation could represent how much

you would spend to join the club and rent movies for a year?
A c=12+25m
B c=25+2m
C c=12m+2
D c=25m+24
Mathematics
1 answer:
tia_tia [17]2 years ago
7 0

<u>Answer:</u>

The correct answer option is B. c = 25 + 2m.

<u>Step-by-step explanation:</u>

We are given that a movie rental club charges a one time fee of $25 to join and $2 for every movie rented.

We are to determine whether which of the given equations in the answer options represent how much you would spend to join the club and rent movies for a year.

The correct answer option is B. c = 25 + 2m.

One time charges = 25 plus $2 multiplied by the number of movies rented.

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inn [45]

Answer:

t = 17.3

Step-by-step explanation:

The following data were obtained from the question:

Angle T = 87°

Opposite T = t =?

Opposite V = v = 14

Opposite U = u = 11

The value of t can be obtained by using cosine rule formula as shown below:

t² = v² + u² – 2vu CosT

t² = 14² + 11² – 2 × 14 × 11 × Cos87°

t² = 196 + 121 – 308 × Cos87°

t² = 317 – 16.119

t² = 300.881

Take the square root of both side

t = √300.881

t = 17.3

Therefore, the value of t is 17.3

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2.55

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A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng
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Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, xy \leq 8000

So,x(220-x) \leq 8000

220x-x^2 \leq 8000

So,220x-x^2 = 8000\\-x^2+220x-8000=0

General quadratic equation : ax^2+bx+c=0

Formula : x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0
3 years ago
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