The diagram shows that FG = IJ are congruent segments due to the double tickmarks. These are the hypotenuses of the right triangles.
So that takes care of the "H" in "HL".
The L stands for "leg", so we need to have a congruent pair of corresponding legs.
Due to the orientation of the triangles, it's not clear how the corresponding legs match up, but if any of the following is true
- EF = IK
- EF = JK
- EG = IK
- EG = JK
then we'd have enough to use HL.
Answer:
There are 5 terms in the series.
Step-by-step explanation:
Take logs to get n = 5
Hi there!
f(x) = -3x² + 11x + 37
Substitute in 4 for x to find f(4):
f(4) = -3(4)² + 11(4) + 37
f(4) = -3(16) + 44 + 37
f(4) = -48 + 44 + 37
f(4) = 33
Answer:
C
Step-by-step explanation:
The sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 1 and d = 3, thus
= 1 + 3(n - 1) = 1 + 3n - 3 = 3n - 2 → C
Answer:
See below.
Step-by-step explanation:
Here is one pair of angle of each type. There are more correct answers.
corresponding angles: <K, <O
alternate interior angles: <N, <P
alternate exterior angles: <I, <S
same-side interior angles: <N, <Q
vertical angles: <P, <R
supplementary angles: <J, <M
