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Ber [7]
3 years ago
5

A bacteria culture has 2,000 bacteria. The number of bacteria increases by 5% each hour. How many bacteria are there after 12 ho

urs?
Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0
Suppose the number of bacteria are increasing exponentially, We can model the number of bacteria at a given time t, using the formula:
f(t)=ae(tk)
where, k=constant of proportionally and a=initial number;
thus;
f(t)=2000e(0.005t)
Therefore the population after 12 hours will be:
f(12)=2000e^(0.005*12)
f(12)=2,123.67=2,123 bacteria
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Find the product: Negative 4 over 9 and Negative 3 over 8.
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Answer:

4/9 x 3/8 = 1/6

Step-by-step explanation:

3 0
2 years ago
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
PLS HELP<br> What is the area, in square of the parallelogram below?
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What is the area of this compound shape?
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first you do 8*8 because that would be the area of the square part

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75.36+64

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6 0
3 years ago
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