Point t slope form:
y + y value = m (x + x value) where m is the gradient
Parallel line must have the same gradient as the two lines never meet, so the gradient must be 4. This eliminates option B and D.
Remember that point-slope form is still an equation, so the values of both sides must be equal. So let's substitute the given coordinates.
Option A:
y-6=4(x+2)
-6-6 (-12) does not equal to 4(-2+2) (0)
Option C:
y+6=4(-2+2)
-6+6 (0) = 4(-2+2) (0)
Therefore, option C is your answer.
Answer:
y = -3x + 8
Step-by-step explanation:
This looks like it's in slope-intercept form.
So, they want you to write it like y=mx+b, where m is the slope and b is the y-intercept.
First, find the slope.
The slope is calculated by using: ![\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
You have several points. Let's use (1,5) and (2,2)
= 2
= 5
= 2
= 1
=
= -3
The slope (m) is -3.
y = -3x + b
Now, find the y-intercept.
Substitute points in for y and x.
Let's use (1,5) (x,y)
x= 1
y=5
5= -3(1) +b
5 = -3 + b
b = 8
Add b to your equation.
y = -3x + 8
Answer:
12.08-1.42=10.66
it takes 10.66 minutes on Thursday to run a mile
Answer:
Step-by-step explanation:
Given is the results of a hypothesis testing for sample mean with population mean.
![H_0; \bar x = 88\\H_a: \bar x \neq 88](https://tex.z-dn.net/?f=H_0%3B%20%5Cbar%20x%20%3D%2088%5C%5CH_a%3A%20%5Cbar%20x%20%5Cneq%2088)
(Two tailed test at 1% significance level)
Reason:Two tailed because confidence interval is (100,136) with mean =118
Significance level = 100-confidence level
Given that confidence interval is (100,136)
i.e. we can be 99% confident that if samples for large sizes are drawn from this population will have mean within this interval
In this case sample mean 88 does not fall within this interval
Hence our null hypothesis has to be rejected
X+8
The equation of that line from from picture is -x+4
2/2=1 with y intercept on 4
Since if is perpendicular we can assume that the equation should be positive. Eliminate the negative answers.
Negative reciprocal= x+1/4