So attached is a picture of the triangle you are talking about and listed under are the choices:

A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
D.) Tan Z=a/b

The answer would then be B. SinX = c/b.

Just remember SOH CAH TOA:

Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent

Using the triangle in the scenario, you just need to identify which side is which.

Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c

SinZ= a CosZ = b TanZ= a
c c b

Given m∠X:

Adjacent = b
Opposite = a
Hypotenuse = c

SinX= b CosX = a TanX= b 
c c a

So the answer is B.

Attached is a picture of how I assigned the sides depending on the angle used.

4 0

3 years ago

3b^2-4b+1=0 solve each equation with the quadratic formula

hjlf

First multiply 3 and the 1
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve