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3 years ago

HELP PLEASE AND THANK YOU 4JAAB

Mathematics

1 answer:

Maslowich3 years ago

7 0

Answer:

$\bold{Q13}\ \angle W\\\\\bold{Q14}\ \angle S\\\\\bold{Q15}\ side\ WA\\\\\bold{Q16}\ \triangle PTA$

Step-by-step explanation:

For Q13, Q14, Q15

$\text{for}\ \overline{WA}\ \text{and}\ \overline{AS}\ -\ A\ \text{is common}.\ \text{Therefore inclu}\text{ded angle is}\ \angle A\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{WA}\to\angle W\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{SA}\to\angle S\\\\============================$

$\text{Inc}\text{lude side between}\ \angle A\ \text{and}\ \angle W\ \text{is}\ AW\ (WA).\\\\\text{Inc}\text{lude side between}\ \angle S\ \text{and}\ \angle W\ \text{is}\ SW\ (WS).\\\\\text{Inc}\text{lude side between}\ \angle A\ \text{and}\ \angle S\ \text{is}\ AS\ (SA).$

Q16

$O\ \leftrightarrow\ T\\B\ \leftrightarrow\ A\\R\ \leftrightarrow\ P\\\\\text{Therefore}\ \triangle ROB\ \cong\ \triangle PTA$

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Round 23.5481 to the nearest thousandth

NemiM [27]

Answer: 23.548

Step-by-step explanation: The thousandths place is 3 places to the right of the decimal point so in this problem, the digit in the rounding place is 8.

The rules of rounding says that if the digit to the right of the rounding place is greater than or equal to 5, we round down but if the digit to the right of the rounding place is less than 5, we round down.

Since the digit to the right of the rounding place, 1, is less than 5, we round down. This means that the digit in the rounding place which is 8 stays the same and we change all digits to the right of 8 to zero.

So we have 23.5480.

Finally, it's important to understand that when rounding decimals, we can drop any zeroes to the right of the decimal point as long as they're also to the right of the rounding place.

This means that 23.5481 rounded to the nearest thousandth is 23.548.

5 0

4 years ago

Mike observed that 75% of the students of a school liked skating. If 35 students of the school did not like skating, the number

Allisa [31]

If 75% liked skating, then 25% did not
so 25% of what is 35
0.25x = 35
x = 35/0.25
x = 140...so there is a total of 140 students

75% of 140 =
0.75(140) = 105...so 105 students liked skating

7 0

3 years ago

Solve -4(2x - 1) = -6(x + 2) - 2 A.-5 B.5 C.9 D.9

Oksanka [162]

$Hello$ $There!$

The answer is...

C. 9

Hopefully, this helps you!!

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3 years ago

-4/4 + 160% + 1/5=????

kifflom [539]

Answer:

-4/4+160% of +1/5= -0.68 or 8/25

Step-by-step explanation:

-4/4+160% of +1/5

-1 + 160% of + 1/5

-1 + 160% of + 0.2

-1 + 0.32

-0.68 as a decimal

and

8/25 as a fraction

8 0

4 years ago

A lot of 25 skylight covers are received at your construction site, and before installation are subjected to an acceptance testi

8090 [49]

Answer:

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

Step-by-step explanation:

We have a population of N=25 skylight covers, were K=4 are defective.

We sample n=5 covers, and we will accept the lot if k=2 or fewer are defective.

We will use the hypergeometric distribution to model this probabilities.

First, to be accepted, the sample can have 2, 1 or 0 defective covers, so the probability of being accepted is:

$P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)$

The probability that there are k defective covers in the sample is:

$P(k)=\dfrac{\dbinom{k}{k}\dbinom{N-k}{n-k}}{\dbinom{N}{n}}$

Then, we can calculate the individual probabilities as:

$P(k=0)=\dfrac{\dbinom{4}{0}\cdot \dbinom{25-4}{5-0}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{0}\cdot \dbinom{21}{5}}{\dbinom{25}{5}}\\\\\\P(k=0)=\dfrac{1\cdot 20349}{53130}=0.38$

$P(k=1)=\dfrac{\dbinom{4}{1}\cdot \dbinom{25-4}{5-1}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{1}\cdot \dbinom{21}{4}}{\dbinom{25}{5}}\\\\\\P(k=1)=\dfrac{4\cdot 5985}{53130}=0.45$

$P(k=2)=\dfrac{\dbinom{4}{2}\cdot \dbinom{25-4}{5-2}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{2}\cdot \dbinom{21}{3}}{\dbinom{25}{5}}\\\\\\P(k=2)=\dfrac{6\cdot 1330}{53130}=0.15$

If we add this probabilities, we have:

$P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)\\\\P(accepted)=0.38+0.45+0.15=0.98$

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

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3 years ago