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zhuklara [117]
3 years ago
9

Is this equation linear or nonlinear? 5xy + 4 = 9

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0

It is definitely linear

Akimi4 [234]3 years ago
5 0
5xy+4=9

5xy=5

xy=1

y=1/x

So this is of the form kx^(-1), this is not linear as the rate of change is not constant...only kx^1 will have a constant rate of change and be linear.

If you graph it you will see that it is exponential....definitely not a straight line :P
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What is the ratio
storchak [24]
9;9
Explanation:
You divide 18 by 2 to get 9 and divide 27 by 3 to get 9.

Hope that helps!

3 0
3 years ago
Frieda has 12 red apples and 15 green apples. She is going to share the apples equally among 8 people and keep any extra apples
icang [17]

Answer:

3

Step-by-step explanation:

She has 12+15=27 apples

We divide 27 by 8 people

27:8=3

-24

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(3)

We have reminder 3 so, she have 3 apples for herself.

5 0
3 years ago
A person has an unknown element with a volume of 16 cubic inches and a weight of 4.13 pounds.
yawa3891 [41]
Answer is A.Zinc
If it not it still Zinc

7 0
2 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
The total cost of a $112.75 meal with a 20% tip​
irinina [24]

Answer:

$135.30

Why:

Take the 112.75 and multiply it by 1.2, or in other words 120%. You get 135.3, or in a money situation, $135.30. Good luck.

8 0
3 years ago
Read 2 more answers
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