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3 years ago

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Mathematics

1 answer:

Tanya [424]3 years ago

7 0

2 is the answer to 1+1

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The Practical Investment Club has 13 members with equal shares. Their total investment to date is $24,689.55. How much is the

Sati [7]

Number of members = 13
Total investment = $24,689.55

Since they have equal shares, dividing the total investment with number of members gives shares value per member.

That is
Value of shares per member = $24,689.55/13 = $1,899.20

4 0

3 years ago

Read 2 more answers

Solve for y.<br><br> y – (-5) = -7

Mice21 [21]

y-(-5)=-7

y+5=7

y+5-5=7-5

y=2

5 0

3 years ago

Read 2 more answers

Compare 0.55 ____ 0.525 using , or =

fredd [130]

Answer:

0.55 > 0.525

Step-by-step explanation:

3 0

3 years ago

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A Ski resort tracks the proportion of seasonal employees who are rehired each season. Rehiring a seasonal employee is beneficial

DaniilM [7]

The test statistic z will be equal to -0.946 and it shows that there is no significant difference in the proportion of rehires between full time and part time.

Given sample sizes of 833 and 386 and result of samples 434 and 189.

$n_{1} =833, n_{2}=386$

Proportion of full time=434/833=0.52

Proportion of part time=189/386=0.49.

Difference in proportion =0.52-0.49

$H_{0}:$ TTF- i∈ rho=0

$H_{1}:$ TTF+i∈ rho≠0.

Mean of difference=0.03

Z=(X-μ)/σ

σ= $\sqrt{0.4517/447}$

=0.0317

σ=0.0317

z=(0-0.03)/0.0317

=-0.03/0.0317

=-0.317

p value will be =0.1736.

Because p value is greater than 0.01 so we will accept the null hypothesis which shows that there is no significant difference in the proportions.

Hence there is no significant difference in the proportion of rehires between full time and part time.

Learn more about z test at brainly.com/question/14453510

#SPJ4

6 0

2 years ago

L'hopital's Rule Problem

Airida [17]

$\displaystyle\lim_{x\to\pi/2^-}\left(x-\frac\pi2\right)\sec x=\lim_{x\to\pi/2^-}\frac{x-\frac\pi2}{\cos x}$

Since $\cos\dfrac\pi2=0$ , this limit yields the indeterminate form $\dfrac00$ . By L'Hopital's rule, we have

$\displaystyle\lim_{x\to\pi/2^-}\dfrac1{-\sin x}$

and since $\sin\dfrac\pi2=1$ , we end up with -1 as the limit.

7 0

3 years ago