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Harlamova29_29 [7]
3 years ago
10

Match the expressions with their resultant terms in exponential form

Mathematics
kingrabbitt
3 years ago
has anyone awnserd this
2 answers:
jasenka [17]3 years ago
5 0
The First expression is 13 to the 1st power.  the second expression is 13 to the -22nd power. third expression is 13 to the 15th power fourth expression is 13 to the 7th power.
irga5000 [103]3 years ago
5 0

Answer:

Step-by-step explanation:

Resultant Terms in Exponential form                            Tiles

1. 13^{-11}{\times}13^{16}{\times}13^{-3}{\times}13^{4}{\times}13^{-5}=13^{-19+20}                           13^1

2.13^{-21}{\times}13^{-4}{\times}13^{-5}{\times}13^{14}{\times}13^{-6}=13^{-36+14}                         13^{-22}

3. 13^{33}{\times}13^{-2}{\times}13^{5}{\times}13^{-13}{\times}13^{-8}=13^{38-23}                            13^{15}

4. 13^{0}{\times}13^{10}{\times}13^{-12}{\times}13^{5}{\times}13^{4}=13^{19-12}                                13^{7}

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a father and son are digging a garden that is 7 feet wide. the father, working alone, can dig the garden in 3 hours. The son can
Anna71 [15]
There is a formula for this. (see attached)

Time = 3 * 4 / (3+4)
Time = 12 / 7
Time = <span> 1.714286 </span>
Time = <span> 1.7 (rounded)


</span>


3 0
3 years ago
The circumference of a circle is 25.12 miles. What is the circle's diameter? C=25.12 mi Use 3.14 for ​pi
svetoff [14.1K]
The answer to your question is 8mi. I just divide the circumference by pi to find your diameter.
8 0
3 years ago
Read 2 more answers
The product of the square of a number and 5
bearhunter [10]
Let the number be x, the square of x is x^2, then
The product of the square of x and 5 is 5x^2.

5 0
4 years ago
Please help, no links
Colt1911 [192]

Answer:

m<1=90°

m<2=38°

hope this helps

4 0
3 years ago
The no. Of adel beads to that of claire's beads was the ratio 7 :4 .When adel gave 68 beads to claire the ratio become 25 :41 .
Novosadov [1.4K]

Answer:

37 beads

Step-by-step explanation:

Given that:

Adel : Claire = 7 : 4

Let Adel be = A;  &

Let Claire be = C

A: C = 7 : 4

\dfrac{A}{C} =\dfrac{7}{4}

7C = 4A

C = \dfrac{4A}{7} --- (1)

When Adel gave 68 beads to claire, we have:

C + 68 = 25:41

\dfrac{A}{C+68}= \dfrac{25}{41}

25(C + 68) = 41A

C + 68 = \dfrac{41}{25}A

C = \dfrac{41}{25}A - 68 --- (2)

Equating (1) and (2) together;

\dfrac{4 * A}{7} = \dfrac{41 *A}{25} - 68

\dfrac{4 * A}{7}-\dfrac{41 *A}{25} =  - 68

\dfrac{100A - 287 A}{175} =- 68

\dfrac{-187A}{175} = -68

- 187 A = 175 × (-68)

-187 A = - 11900

A = - 11900/ -187

A ≅ 64

From; C = \dfrac{4A}{7}

C = \dfrac{4*64}{7}

C = 36.57

C ≅ 37 beads

4 0
3 years ago
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