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insens350 [35]
3 years ago
8

What is the value of p? x^2=12y

Mathematics
2 answers:
lora16 [44]3 years ago
7 0
x^2=4py
\\x^2=12y
\\4p=12
\\p=3
Nata [24]3 years ago
5 0
There is no variable 'p' in this equation, what are you looking for?
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What is mBCD. Please help. Quickly
Flauer [41]

Answer:

82°

Step-by-step explanation:

m÷ BAD + m÷ BCD = 180°

98° + m÷BCD = 180°

m÷BCD = 180° - 98°= <u> </u><u>8</u><u>2</u>°

6 0
2 years ago
Identify whether each set of ordered pairs is a function or is not a function. Function Not a Function
Anna35 [415]

Answer:

1. Function

2. Function

3. Function

4. Not a Function

5. Not a Function

Step-by-step explanation:

Hope it helps:)

7 0
2 years ago
Find the size of the marked angles​
morpeh [17]

Answer:

b = 55°

c = 35°

Step-by-step explanation:

b° = 180° - (85°+40°) = 180° - 125° = 55°

c° = 180° - (b°+90°) = 180° - (55°+90°) = 180° - 145° = 35°

3 0
3 years ago
Read 2 more answers
20 points!!!!!!!
castortr0y [4]
See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid

we know that
One edge of the cuboid has length 2 cm----->  <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1

[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]

100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0

using a graph tool------> to resolve the second order equation
see the attached figure

the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm

<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm

the answer is
 the length of a diagonal of the cuboid is 13.75 cm



4 0
3 years ago
Which of the following are solutions to the system graphed below.
Kisachek [45]
Weird. I think you just need to look if the point falls on the shaded area. But only (-5,5) does ...

4 0
3 years ago
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