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artcher [175]
3 years ago
12

What is the solution to this inequality? 7x-4<4 (x+3)

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0
<h2>Steps</h2>

7x - 4 < 4 ( x + 3 )

Let's start with this part of the inequality: 4 ( x + 3 )

Apply the distributive law: <u>a ( b + c ) = ab + ac</u>

<u>a = 4, b = x, c = 3</u>

= 4x + 4 x 3

Multiply the numbers: 4 x 3 = 12

= 4x + 12

Plug in the values:

7x - 4 < 4x + 12

Add 4 to both sides

7x - 4 + 4 < 4x + 12 + 4

Simplify

7x < 4x + 16

Subtract 4x from both sides

7x - 4x < 4x + 16 - 4x

Simplify

3x < 16

Divide both sides by 3

3x / 3  <  16 / 3

Answers:

x < 16 / 3  or...

x < 5.33(repeating)

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we are given

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An e-commerce research company claims that 60% or more graduate students have bought merchandise on-line at their site. A consum
Elena-2011 [213]

Answer:

z=\frac{0.55 -0.6}{\sqrt{\frac{0.6(1-0.6)}{80}}}=-0.913  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduate students show that only 44 students have ever done so is not significantly lower than 0.6

Step-by-step explanation:

Data given and notation

n=80 represent the random sample taken

X=44 represent the students that have bought merchandise on-line at their site

\hat p=\frac{44}{80}=0.55 estimated proportion of graduate students show that only 44 students have ever done so

p_o=0.6 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of interest is lower than 0.6 or 60%, so then the system of hypothesis are.:  

Null hypothesis:p \geq 0.6  

Alternative hypothesis:p < 0.6  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.55 -0.6}{\sqrt{\frac{0.6(1-0.6)}{80}}}=-0.913  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed for this case is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduate students show that only 44 students have ever done so is not significantly lower than 0.6

5 0
3 years ago
I not need i is smaat
Slav-nsk [51]

Answer:

Sorry, what's your direct question here.

3 0
3 years ago
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