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emmainna [20.7K]
3 years ago
8

[4|16-38|+6]-17•2

Mathematics
1 answer:
Maurinko [17]3 years ago
3 0

\bf \underset{\textit{we start from the innermost}}{\stackrel{\mathbb{PEMDAS}}{[4|16-38|+6]-17\cdot 2}}\implies [4\cdot |\stackrel{\downarrow }{-22}|+6]-17\cdot 2\implies [4\cdot \stackrel{\downarrow }{22}+6]-17\cdot 2 \\[2em] [\stackrel{\downarrow }{88}+6]-17\cdot 2\implies \stackrel{\downarrow }{94}-17\cdot 2\implies 94-\stackrel{\downarrow }{34}\implies 60

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Alenkasestr [34]

Answer:

by increasing the size ez

4 0
3 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
What are the zeros of the polynomial function y=2x^3-7x^2+2x+3?
zlopas [31]

y = 2 {x}^{3}  - 7 {x}^{2}  + 2x + 3

By inspection 1 is a root of y ,
Hence , (x-1) is a factor of y ,

\dfrac{2 {x}^{3} - 7 {x}^{2}  + 2x + 3 }{x - 1}  = 2 {x}^{2}  - 5x - 3 \\  \\ 2 {x}^{2}  - 5x - 3 = (2x + 1)(x - 3)

Hence , the 2 other roots are -1/2 and 3 , and the above graphs confirms the same.

Hope it helps you :)

7 0
3 years ago
A parabola intersects the xxx-axis at x=3x=3x, equals, 3 and x=9x=9x, equals, 9.
vekshin1

Answer:

x^2-12x+27 =0

Step-by-step explanation:

Given a Parabola that intersects the x-axis at x=3 and x=9.

I presume you want to determine the equation of the parabola.

You can use this form:

Given roots of a parabola, the equation of the parabola is derived using the formula:

x^2-($Sum of Roots)x+Product of Roots =0\\Since roots are 3 and 9, the equation becomes:\\x^2-(3+9)x+(3X9) =0\\x^2-12x+27 =0

The equation of the parabola is:

x^2-12x+27 =0

8 0
3 years ago
A bag hold 1 blue block and 3 yellow block. How many green Blocks should be added to the bag to makr the probability of randomly
Natasha_Volkova [10]

Hello,

Since there is 1 blue block and 3 yellow blocks that would equal to 4 blocks in total. So the question is asking how many green blocks would be needed to make it 1/2. So you would be needing 4 green blocks to make the probability of randomly selecting a green block from the bag to equal 1/2.

I hope this helped you!


8 0
2 years ago
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