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emmainna [20.7K]
4 years ago
8

[4|16-38|+6]-17•2

Mathematics
1 answer:
Maurinko [17]4 years ago
3 0

\bf \underset{\textit{we start from the innermost}}{\stackrel{\mathbb{PEMDAS}}{[4|16-38|+6]-17\cdot 2}}\implies [4\cdot |\stackrel{\downarrow }{-22}|+6]-17\cdot 2\implies [4\cdot \stackrel{\downarrow }{22}+6]-17\cdot 2 \\[2em] [\stackrel{\downarrow }{88}+6]-17\cdot 2\implies \stackrel{\downarrow }{94}-17\cdot 2\implies 94-\stackrel{\downarrow }{34}\implies 60

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The sum of three numbers $x$ ,$y$, $z$ is 165. When the smallest number $x$ is multiplied by 7, the result is $n$. The value $n$
babymother [125]

You're given

<em>x</em> + <em>y</em> + <em>z</em> = 165

7<em>x</em> = <em>n</em>

<em>n</em> = <em>y</em> - 9

<em>n</em> = 9 + <em>z</em>

and you want to find <em>xyz</em>.

Solve the last three equations for <em>x</em>, <em>y</em>, and <em>z</em> :

7<em>x</em> = <em>n</em>   →   <em>x</em> = <em>n</em>/7

<em>n</em> = <em>y</em> - 9   →   <em>y</em> = <em>n</em> + 9

<em>n</em> = 9 + <em>z</em>   →   <em>z</em> = <em>n</em> - 9

Substitute <em>x</em>, <em>y</em>, and <em>z</em> into the first equation and solve for <em>n</em> :

<em>n</em>/7 + (<em>n</em> + 9) + (<em>n</em> - 9) = 165

<em>n</em>/7 + 2<em>n</em> = 165

<em>n</em> + 14<em>n</em> = 1155

15<em>n</em> = 1155

<em>n</em> = 77

Now solve for <em>x</em>, <em>y</em>, and <em>z</em> :

<em>x</em> = 77/7 = 11

<em>y</em> = 77 + 9 = 86

<em>z</em> = 77 - 9 = 68

Then the product is

<em>xyz</em> = 11 • 86 • 68 = 64,328

6 0
3 years ago
81 x 11<br> 73 x82<br> 64 x 55<br> 27 x 63<br> 24 x 25<br> 47 x 63<br> 24 x 44
zubka84 [21]
81 times 11 is 891
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4 0
3 years ago
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MakcuM [25]

Step-by-step explanation:

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8 0
3 years ago
How do you find the first five terms of a sequence defined recursively
Blizzard [7]
Interesting question. Good to know for computer science.
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I'll do one more and then check it.
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So the general formula is
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Yes it makes since both answers come out to 2.236
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