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kenny6666 [7]
3 years ago
15

Write the equation of a line that is perpendicular to the given line and that passes through the given point 2x+9y=-30;(-8,0)

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
6 0
Y=(-30-2x)/9 the slop is -2/9 because perpendicular to the given line so the new slop is 9/2
y=9/2x+b
0=9/2*-8+b
0=-36+b
b=36
y=9/2x+36 is the answer
telo118 [61]3 years ago
3 0

Answer:

y=\frac{9}{2}x+36

Step-by-step explanation:

The given equation is 2x+9y=-30.

Subtracting 2x both sides :

9y=-2x-30

Dividing both sides by 9 we have:

y=\frac{-2}{9}x -\frac{10}{3}

This equation is of the form y=mx+b where the slope m=\frac{-2}{9}

Slope of a perpendicular line =\frac{9}{2}

The perpendicular line passes through the point (-8,0)

The equation of the perpendicular line is :y-0=\frac{9}{2} (x+8)

Or y=\frac{9}{2}x+36

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