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kenny6666 [7]
3 years ago
15

Write the equation of a line that is perpendicular to the given line and that passes through the given point 2x+9y=-30;(-8,0)

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
6 0
Y=(-30-2x)/9 the slop is -2/9 because perpendicular to the given line so the new slop is 9/2
y=9/2x+b
0=9/2*-8+b
0=-36+b
b=36
y=9/2x+36 is the answer
telo118 [61]3 years ago
3 0

Answer:

y=\frac{9}{2}x+36

Step-by-step explanation:

The given equation is 2x+9y=-30.

Subtracting 2x both sides :

9y=-2x-30

Dividing both sides by 9 we have:

y=\frac{-2}{9}x -\frac{10}{3}

This equation is of the form y=mx+b where the slope m=\frac{-2}{9}

Slope of a perpendicular line =\frac{9}{2}

The perpendicular line passes through the point (-8,0)

The equation of the perpendicular line is :y-0=\frac{9}{2} (x+8)

Or y=\frac{9}{2}x+36

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Please answer this correctly
lozanna [386]

Answer:

no it to low

Step-by-step explanation:

the answer was 4998

8 0
3 years ago
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
Janelle has a 12-ounce can of soft drink. She drinks 3/5 of the soft drink.
guapka [62]

Answer:

Answer:  4.8 ounces

Step-by-step explanation:

In total there are 12 ounces. If she drinks 3/5 of 12 you multiply 3/5 by 12.

3/5 * 12 would be equal to 3/5 * 12/1 which is 36/5. You have found how much she has drank. 36/5 is also equal to 7.2 ounces. Subtract 7.2 form 12 and you get 4.8 ounces.

Hope this helped!

7 0
3 years ago
Read 2 more answers
Seven - twelfths of a new dress has been sewn. Chelsea did 3/7 of the sewing. How much of the dress did Chelsea sew?
galina1969 [7]
1/4, because 7/12×3/7=1/4
7 0
3 years ago
Can someone please explain to me how to do this?
OLga [1]

Answer:

  1. (-10x -5) -(-7x -4)

  2. (-10x -5) -(-3x -1)

Step-by-step explanation:

The process of simplifying an expression generally involves eliminating parentheses, collecting terms, simplifying fractions, rationalizing denominators, removing appropriate factors from under radicals, and generally putting expressions into general form.

So, to accomplish what the problem is asking, you can create an expression that requires you accomplish as many or as few of these steps as you may like.

In general, you will want to both "do" and "undo" whatever operation(s) you may choose. For example, consider a couple of expressions "a" and "b". For this example, we want our final result to simplify to "a".

If we choose to add "b", we might have ...

  (a+b) -b . . . . . we have both added and subtracted b, so the simplified result is "a"

If we choose to multiply by "b", we might have ...

  (ab)/b . . . . . . we have both multiplied by b and divided by b, so the simplified result is again "a"

_____

We can solve both these problems at once by using ...

  • a = -3x -1
  • b = -7x -4

If we choose the first approach, we want an expression that is (a+b). That will be ...

  a+b = (-3x -1) +(-7x -4) = -10x -5

By subtracting "b" from this expression, we get "a"--and vice versa. That is ...

  1. (-10x -5) -(-7x -4) . . . simplifies to . . . -3x -1
  2. (-10x -5) -(-3x -1) . . . simplifies to . . . -7x -4

_____

<em>Alternate solution to 2</em>

Suppose we choose to multiply instead. Let "b" be -3x+2. Then, using the template for multiplication above, we can write the expression

  (-7x -4)(-3x +2)/(-3x +2) = (21x^2 -2x -8)/(-3x +2)

and we know this rational expression simplifies to -7x -4.

_____

Of course, we can be as elaborate as we might like in modifying the original expression. Whatever we do, we must also include the "undo" so the original expression is recovered when we simplify. To illustrate the point, we can add and subtract 2x from the above rational expression.

  ((21x^2 -2x -8)/(-3x +2) + 2x) - 2x = (21x^2 -2x -8 +2x(-3x +2))/(-3x +2) - 2x

  = (21x^2 -2x -8 -6x^2 +4x)/(-3x +2) -2x

  = (15x^2 +2x -8)/(-3x +2) -2x . . . . . . another alternate solution to #2.

If we're not careful, we can create an expression that is extremely difficult to simplify. The one we have here can be factored to be ...

  (-5x -4)(-3x +2)/(-3x +2) -2x = -5x -4 -2x = -7x -4 . . . our original #2 expression

Knowing that it <em>can</em> be factored is a big help.

6 0
3 years ago
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