Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point 2x+9y=-30;(-8,0)

Answer 1

Y=(-30-2x)/9 the slop is -2/9 because perpendicular to the given line so the new slop is 9/2
y=9/2x+b
0=9/2*-8+b
0=-36+b
b=36
y=9/2x+36 is the answer

Answer 2

Answer:

$y=\frac{9}{2}x+36$

Step-by-step explanation:

The given equation is 2x+9y=-30.

Subtracting 2x both sides :

9y=-2x-30

Dividing both sides by 9 we have:

$y=\frac{-2}{9}x -\frac{10}{3}$

This equation is of the form y=mx+b where the slope m=$\frac{-2}{9}$

Slope of a perpendicular line =$\frac{9}{2}$

The perpendicular line passes through the point (-8,0)

The equation of the perpendicular line is :$y-0=\frac{9}{2} (x+8)$

Or $y=\frac{9}{2}x+36$