Can someone please help me with this

Help pls :))))))))))))

Aneli [31]

Answer:

yes, the triangle are congruent by SAS

6 0

2 years ago

If you have 2 different slopes what is true about the slopes

Anna007 [38]

Answer:

Step-by-step explanation:

If two lines have different slopes, they cannot be the same line. If they share a y-intercept, that means they cross the y -axis at the same y value. If they share an x value and corresponding y value, they intersect at that point, in this case their y-intercept.

Hope this helped!!

8 0

2 years ago

A cone has a volume of 5 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?

Naya [18.7K]

<span>Volume of Cone: 1/3 Bh where B is the area of the base 1/3 Bh = 5 Bh = 15 B = 15/h The cylinder has the same base area as the cone. Volume of Cylinder: V = B*h B = V/h and B = 15/h The height of the cone and the cylinder are the same. V/h = 15/h Volume of Cylinder = 15.</span>

4 0

2 years ago

Solve the following equation by completing the square. 3x^2-3x-5=13

mr Goodwill [35]

we'll start off by grouping some

$\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6$

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

$\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2$

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

$\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}$

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

$\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}$

6 0

2 years ago

Terry added 3 and 7 he got the sum of 9 his answer is is not correct described how Terry can find the correct sum

exis [7]

O it is not correct he can find the correct sum by counting and adding 8,9,10 so the answer is ten he was one of his answer he must not of counted right

5 0

2 years ago

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