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Anton [14]
4 years ago
9

If the zookeeper had 100 pairs of animals in her zoo and if two pairs of babies are born for each and every one of the original

animals,and then sadly 23 animals don’t survive,how many animals do you have left in total?
Mathematics
2 answers:
Naddika [18.5K]4 years ago
4 0

Answer:

177 animals

Step-by-step explanation:

So, you have 100 animals, multiply by 2 because you have 2 animals born PER original animal.

You then have 200 animals, but 23 don't survive. therefore you subtract the 23 from 200.

you will have 177 animals

Ksenya-84 [330]4 years ago
3 0

Answer:

287

Step-by-step explanation:

Since 2 pairs of babies are born from each and every one of the animals, that means there are 200 babies. You add 100 to 200 and get 300 and then subtract 23, which gives 287 animals left.

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3 years ago
For a field trip 9 students rode in cars and the rest filled three busses. How many students were in each bus if 99 students wer
taurus [48]

Answer: 30 students per bus

Step-by-step explanation: 99-9=90

90/3=30

30 students per bus

8 0
4 years ago
A and ∠B are complementary angles. If m∠A is 35LaTeX: ^\circ∘, what is the measure of B?
ipn [44]
Since they are complementary, they both add up to 90 degrees. So, 90-35=55 degrees.

The measure of angle B is 55 degrees.
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3 years ago
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Mrs Amnda du Toit purchase the lounge
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6 0
2 years ago
The third and the sixth term of a geometric progression are 24 and 64/9 respectively. Find
Ratling [72]

Answer:

Ai. Common ratio = 2/3

Aii. First term = 54

B. Sum of the first five terms = 422/3

Step-by-step explanation:

From the question given above, the following data were obtained:

3rd term (T3) = 24

6Th term (T6) = 64/9

First term (a) =?

Common ratio (r) =?

Sum of the first five terms​ (S5) =?

Ai. Determination of the common ratio (r).

T3 = ar²

T3 = 24

24 = ar²....... (1)

T6 = ar⁵

T6 = 64/9

64/9 = ar⁵......... (2)

The equation are:

24 = ar²....... (1)

64/9 = ar⁵......... (2)

Divide equation 2 by equation 1.

64/9 ÷ 24 = ar⁵ / ar²

64/9 × 1/24 = r³

8/27 = r³

Take the cube root of both side

r = 3√(8/27)

r = 2/3

Thus, the common ratio is 2/3

Aii. Determination of the first term (a).

T3 = ar²

3rd term (T3) = 24

Common ratio (r) = 2/3

First term (a) =?

24 = a(2/3)²

24 = 4a/9

Cross multiply

24 × 9 = 4a

216 = 4a

Divide both side by 4

a = 216/4

a = 54

Thus, the first term (a) is 54

B. Determination of the sum of the first five terms.

Common ratio (r) = 2/3

First term (a) = 54

Number of term (n) = 5

Sum of first five terms (S5) =?

Sn = a[1 –rⁿ] / 1 – r

S5 = 54[1 – (⅔)⁵] / 1 – ⅔

S5 = 54 [1 – 32/243] / ⅓

S5 = 54 (211/243) × 3

S5 = 54 × 211/81

S5 = 6 × 211/9

S5 = 2 × 211/3

S5 = 422/3

Thus, the sum of the first five terms is 422/3

8 0
3 years ago
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