Question

Please help me with this question, image attached

Answer 1

Answer:

$W=(x-6)\ m$

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

we have

$A=(x^{2} -11x+30)\ m^2$

$L=(x-5)\ m$

substitute the given values in the formula of area

$(x^{2} -11x+30)=(x-5)W$

Remember that

$x^{2} -11x+30=(x-5)(x-6)$ ----> by completing the square

substitute

$(x-5)(x-6)=(x-5)W$

Simplify

$W=(x-6)\ m$